I would like to insert data into a table with dynamic field names. My script lists all the column names that need to be inserted with data. I would like the users input for the dynamic fields to be inserted into the table. for example under field Car the data is 1 and Boat data is 0. Here is my script below:
<?php
$connect=mysql_connect('localhost','root','');
$db_select=mysql_select_db('db_run',$connect);
$sql="SELECT column_name FROM information_schema.columns WHERE table_schema = 'db_run' AND table_name = 'run';";
$sql_query=mysql_query($sql);
$runfields=array();
while($rows=mysql_fetch_assoc($sql_query)){
$rows['column_name']."<br>";
$runfields[]=$rows['column_name'];
}
echo '<pre>';
print_r($runfields);
echo '</pre>';
$cntrunfields=count($runfields);
for($c=2;$c<$cntrunfields;$c++){
echo $run=$runfields[$c].'<br>';
echo $results=$_POST[$run];
echo "<form action='' method='post'>";
echo "<select name='$runfields[$c]' id='$runfields[$c]'>
<option value='-1'>Select option</option>
<option value='0'>No</option>
<option value='1'>Yes</option>
</select>";
echo "<input type=\"submit\" name=\"sss\" id=\"sss\" value=\"Submit\" />" ;
echo "</form>";
echo '<br>';
echo $runfields[$c].' is equal to '.$results.'<br>';
}
?>
If my table has 3 column names my form should display 3 new select form tags and be able to submit in a table. As shown in this section.
echo "<form action='' method='post'>";
echo "<select name='$runfields[$c]' id='$runfields[$c]'>
<option value='-1'>Select option</option>
<option value='0'>No</option>
<option value='1'>Yes</option>
</select>";
echo "<input type=\"submit\" name=\"sss\" id=\"sss\" value=\"Submit\" />" ;
echo "</form>";