1

我创建了一个“假日”表，其中包含 3 列[Date]日期格式，[BusinessDay]即 Y/N，[NameofDay] varchar(50)用于假日或周末。周六、周日、圣诞节都被标记为下一个十年。

我现在需要做的是弄清楚如何通过不计算工作日来确定请求需要完成的日期。我已经阅读了阅读和阅读，但没有看到任何有用的东西。在我的脑海里总是很简单。

我要解决的问题：如果请求是“优先”，则截止日期[DueDate]是从请求之日起 10 个工作日，[TransactionDate]如果是“关键”，则截止日期是 5 个工作日。

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3 回答 3

4

由于@Andomar 提出的问题的递归性质，我建议一个替代答案（它也恰好更简单，但需要可用的窗口函数）。这样做是加入日历中晚于 的有效工作日TransactionDate，然后根据id需要为每个请求找到第 5 行或第 10 行：

;WITH cte AS
(
   SELECT *,
         ROW_NUMBER() OVER (PARTITION BY id ORDER BY validDeliveryDate ASC) AS rn
   FROM (
       SELECT requests.*, holiday.Date as validDeliveryDate
       FROM requests
       JOIN holiday
         ON requests.TransactionDate < holiday.Date
         AND DATEADD(day, 25, requests.TransactionDate) >= holiday.Date
         AND holiday.BusinessDay = 'Y' ) v
)
SELECT *
FROM cte
WHERE rn = CASE WHEN critical = 1 THEN 5 ELSE 10 END

不需要迭代 - 在这里工作 sqlfiddle

于 2013-01-03T17:04:35.777 回答
1

计算工作日需要迭代。您添加天数，然后减去非工作日，然后再次添加。

一种方法是使用用户定义的函数：

if exists (select * from sys.objects where name ='WorkingDaysFrom' and type = 'FN')
    drop function dbo.WorkingDaysFrom
go
create function dbo.WorkingDaysFrom(
        @date date
,       @days int)
returns date
as
begin
        declare @result date = @date
        declare @remaining int = @days
        while @remaining > 0
                begin
                set     @result = dateadd(day, @remaining, @result)
                select  @remaining = count(*) 
                from    dbo.Holiday 
                where   [Date] between dateadd(day, 1-@remaining, @result) and @result
                        and BusinessDay = 'N'
                end
        return @result
end
go

SQL Fiddle 上的实时示例。 这打印：

TransactionDate   Priority    DueDate
2013-01-01        Priority    2013-01-16
2013-01-01        Critical    2013-01-09
2013-01-03        Priority    2013-01-17
2013-01-03        Critical    2013-01-10
2013-01-06        Priority    2013-01-18
2013-01-06        Critical    2013-01-11
于 2013-01-03T17:24:09.717 回答
0

我认为以下工作：

select t.*
from (select t.*,
             row_number() over (partition by r.requestid, IsWorkDay order by seqdate) as WorkDayNum
      from (select r.requestid, r.TransactionDate,
                   (case when critical = 1 then 5 else 10 end) as DaysToRespond,
                   dateadd(day, days.seqnum - 1, r.TransactionDate) as seqdate,
                   (case when h.date is null then 1 else 0 end) as IsWorkDay
            from requests r cross join
                 (select top 20 ROW_NUMBER() over (order by (select NULL)) as seqnum
                  from information_schema.columns
                 ) days left outer join
                 holidays h
                 on dateadd(day, days.seqnum - 1, r.TransactionDate) = h.date
           ) t
     ) t
where WorkDayNum = DaysToRespond and IsWorkDay = 1

这是未经测试的，但这是这个想法。

好吧，我已经对此进行了测试，在这种情况下它似乎返回了正确的结果：

with holidays as (
        select CAST('2012-01-01' as date) as date union all
        select CAST('2012-01-05' as date) as date union all
        select CAST('2012-01-06' as date) as date union all
        select CAST('2012-01-12' as date) as date union all
        select CAST('2012-01-13' as date) as date union all
        select CAST('2012-01-19' as date) as date union all
        select CAST('2012-01-20' as date) as date
       ),
      requests as (
        select 1 as requestId, CAST('2012-01-02' as DATE) as TransactionDate, 1 as Critical
      )

select t.*
from (select t.*,
             row_number() over (partition by t.requestid, IsWorkDay order by seqdate) as WorkDayNum
      from (select r.requestid, r.TransactionDate,
                   (case when critical = 1 then 5 else 10 end) as DaysToRespond,
                   dateadd(day, days.seqnum - 1, r.TransactionDate) as seqdate,
                   (case when h.date is null then 1 else 0 end) as IsWorkDay
            from requests r cross join
                 (select top 20 ROW_NUMBER() over (order by (select NULL)) as seqnum
                  from INFORMATION_SCHEMA.columns
                 ) days left outer join
                 holidays h
                 on dateadd(day, days.seqnum - 1, r.TransactionDate) = h.date
           ) t
     ) t
where WorkDayNum = DaysToRespond+1 and IsWorkDay = 1

此查询创建交易日期后 20 天的序列（20 天够吗？）。然后它计算这些天的日期并将日期与假期表进行比较。

计算天数是使用row_number()按请求和工作日与非工作日进行分区。要选择的行是工作日和交易日期之后的天数。

于 2013-01-03T17:21:34.163 回答