可能有按钮子php页面。我想提交按钮的值和使用该值从表中删除记录。Ajaxz 代码是
$('#product-table td #delete').live("click", function () {
var doDelete = confirm('Are you sure you want to delete this record?');
deleteLinkObj = $(this);
if (doDelete) {
var id = $(this).attr('accesskey');
$("#deleteid").val(id);
$.ajax({
url: "purchase.php",
data: {deleteid:id},
dataType: 'html',
success: function() {
}
});
}
else { return false; }
});
在 PHP 上,我正在尝试使用 deleteid 的值,但它没有到来的 PHP 代码是
if(@$_POST['deleteid']!="")
{
$sql="delete from purchasedetails where purchaseid='".$_POST['deleteid']."'";
if(!mysql_query($sql))
{
die('Error: ' . mysql_error());
}
else
{
$msg="Data is deleted";
}
}
我试过使用 isset($_POST['deleteid']) 然后它也显示错误