1

我正在输出购买清单，我想自动突出显示重复订单的存在。

这是数组的样子。前两个订单是错误下的重复订单。您会注意到每个的 orderid 不同，而 email 和 userid 保持不变。因此，重复需要在电子邮件和/或用户 ID 上匹配，而不是在 orderid 上。

array
  0 => 
    array
      'orderid' => string '2009091008261662'
      'email' => string 'john@example.com'
      'userid' => string '53'
array
  1 => 
    array
      'orderid' => string '2009091008261048'
      'email' => string 'john@example.com'
      'userid' => string '53'
array
  2 => 
    array
      'orderid' => string '2009091008262025'
      'email' => string 'fred@example.com'
      'userid' => string '103'
array
  3 => 
    array
      'orderid' => string '2009091008272082'
      'email' => string 'tom@example.com'
      'userid' => string '392'

如何在 PHP 中搜索给定数组中同一个人的重复订单？

我想像这样输出上面的内容：

（假装它在一张桌子上）

2009091008261662 - john@example.com - 53

2009091008261048 - john@example.com - 53

2009091008262025 - fred@example.com - 103

2009091008272082 - tom@example.com - 392

...所以基本上只需突出显示两个（或更多）重复项。

4

6 回答 6

4

基于userid价值假设唯一性

<?php

$orders = array(
  array(
    'orderid' => '2009091008261662',
    'email' => 'john@example.com',
    'userid' => '53'
  ),
  array(
    'orderid' => '2009091008261048',
    'email' => 'john@example.com',
    'userid' => '53'
  ),
  array(
    'orderid' => '2009091008262025',
    'email' => 'fred@example.com',
    'userid' => '103'
  ),
  array(
    'orderid' => '2009091008272082',
    'email' => 'tom@example.com',
    'userid' => '392'
  ),
  array(
    'orderid' => '2009091008265555',
    'email' => 'john@example.com',
    'userid' => '53'
  )
);

$foundIds = array();
foreach ( $orders as $index => $order )
{
  if ( isset( $foundIds[$order['userid']] ) )
  {
    $orders[$index]['is_dupe'] = true;
    $orders[$foundIds[$order['userid']]]['is_dupe'] = true;
  } else {
    $orders[$index]['is_dupe'] = false;
  }
  $foundIds[$order['userid']] = $index;
}
?>

<style type="text/css">
tr.dupe td {
  font-weight: bold;
}
</style>

<table>
  <tr><th>orderid</th><th>email</th><th>
  <?php foreach ( $orders as $order ) { ?>
  <tr class="<?php echo $order['is_dupe'] ? 'dupe' : '' ?>">
    <td><?php echo $order['orderid']; ?></td>
    <td><?php echo $order['email']; ?></td>
    <td><?php echo $order['userid']; ?></td>
  </tr>
  <?php } ?>
</table>
于 2009-09-11T22:52:25.943 回答
1

您最好的选择本质上是将数组“反转”为关联的一个映射值到原始数组中的键：

$emails = array();
$userids = array();

foreach($inputarray as $key => $item) {
    if( isset($emails[$item['email']]) || isset($userids[$item['userid']]) ) {
        // This item has a duplicate email or userid as something already looked at!
        // $emails[$item['email']] or $userids[$item['userid']] has the key corresponding to the original location where it was seen.
        // $key has the key corresponding to the duplicate we just found.
    } else {
        $emails[$item['email']] = $key;
        $userids[$item['userid']] = $key;
    }
}
于 2009-09-11T22:36:21.400 回答
0

您可以将散列添加到表示该数组的内部数组。只需循环并比较哈希值。

于 2009-09-11T22:57:45.950 回答
0

此代码有效...

$array1[0]['orderid'] = '2009091008261662';
$array1[0]['email'] = 'john@example.com';
$array1[0]['userid'] = '53';
$array1[1]['orderid'] = '2009091008261662';
$array1[1]['email'] = 'john@example.com';
$array1[1]['userid'] = '53';
$array1[2]['orderid'] = '2009091008261662';
$array1[2]['email'] = 'john2@example.com';
$array1[2]['userid'] = '53';
$array1[3]['orderid'] = '209091008261662';
$array1[3]['email'] = 'joh3@example.com';
$array1[3]['userid'] = '53';
$array1[4]['orderid'] = '2001008261662';
$array1[4]['email'] = 'john@example.com';
$array1[4]['userid'] = '53';
$array1[5]['orderid'] = '20013344008261662';
$array1[5]['email'] = 'johnddd@example.com';
$array1[5]['userid'] = '53';
$array1[6]['orderid'] = '200133352008261662';
$array1[6]['email'] = 'johsdfgsdn@example.com';
$array1[6]['userid'] = '53';


$unique_array = array(); // Filtered array with no dupes
$email_array = array(); // Hash list
$order_array = array(); // Hash list
foreach($array1 as $i => $row) {

 if (array_key_exists($row['email'], $email_array)) {
  // This is a dupe based on email
  $array1[$i]['duplicate'] = 1;
  $array1[$email_array[$row['email']]]['duplicate'] = 1;
 }

 if (array_key_exists($row['orderid'], $order_array)) {
  // This is a dupe based on email
  $array1[$i]['duplicate'] = 1;
  $array1[$order_array[$row['orderid']]]['duplicate'] = 1;
 }
 $order_array[$row['orderid']] = $i;
 $email_array[$row['email']] = $i;
}
foreach($array1 as $i => $row) {
 if (!empty($row['duplicate'])) {
  echo "<b>" . $row['orderid'] . $row['email'] . "</b>\n";
  unset($row['duplicate']); // reset the array to original form
 } else {
  echo $row['orderid'] . $row['email'] . "\n";
 }
}
于 2009-09-11T23:34:24.297 回答
0

您需要两次传递订单数组。但它确实比某些人认为的要简单：

$duplicateUserId = array();

// Mark user ID's with more than one order
foreach ( $orders as $order ) {
    $duplicateUserId[$order['userid']] = isset($duplicateUserId[$order['userid']]);
}

// Output each order
foreach ( $orders as $order ) {
    echo formatOrder($order, $duplicateUserId[$order['userid']]);
}

// Format the output of each order
function formatOrder($order, $isDuplicated) {
    // yadda yadda yadda
}

假设 $orders 看起来像

$orders = array(
  array(
    'orderid' => '2009091008261662',
    'email' => 'john@example.com',
    'userid' => '53'
  ),
  array(
    'orderid' => '2009091008261048',
    'email' => 'john@example.com',
    'userid' => '53'
  ),
  array(
    'orderid' => '2009091008262025',
    'email' => 'fred@example.com',
    'userid' => '103'
  ),
  array(
    'orderid' => '2009091008272082',
    'email' => 'tom@example.com',
    'userid' => '392'
  ),
  array(
    'orderid' => '2009091008265555',
    'email' => 'john@example.com',
    'userid' => '53'
  )
);

此外，最好只匹配 userId，因为大概用户可以更改他们的电子邮件，并且电子邮件对于单个用户来说是唯一的。

于 2009-09-11T23:48:30.913 回答
-1

简单的回答：

function hasDuplicate($arr,$email) {
  $count = 0;
  foreach ($arr as $row) {
     if ($row['email'] == $email) {
       $count++;
     }
  }
  return ($count >1);
}
于 2009-09-11T22:40:02.130 回答