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我正在根据邮政编码和距离进行搜索以搜索类别。我想要该邮政编码的 10 英里收音机中特定类别的结果。

我的表格格式是

CREATE TABLE IF NOT EXISTS `uk_data` (
  `slno` int(10) NOT NULL AUTO_INCREMENT,
  `comp_name` varchar(150) DEFAULT NULL,
  `comp_no` varchar(50) DEFAULT NULL,
  `comp_street` varchar(100) DEFAULT NULL,
  `comp_area` varchar(100) DEFAULT NULL,
  `comp_post_code` varchar(15) DEFAULT NULL,
  `comp_phone` varchar(100) DEFAULT NULL,
  `comp_phone1` varchar(100) DEFAULT NULL,
  `cat1` varchar(100) DEFAULT NULL,
  `cat2` varchar(100) DEFAULT NULL,
  `cat3` varchar(100) DEFAULT NULL,
  `cat4` varchar(100) DEFAULT NULL,
  `cat5` varchar(100) DEFAULT NULL,
  `cat6` varchar(100) DEFAULT NULL,
  `cat7` varchar(100) DEFAULT NULL,
  `cat8` decimal(9,6) DEFAULT NULL,
  `cat9` decimal(9,6) DEFAULT NULL,
  `cat10` varchar(15) DEFAULT NULL,
  PRIMARY KEY (`slno`),
  UNIQUE KEY `Phone` (`comp_phone`),
  KEY `cat10` (`cat10`)
) ENGINE=MyISAM  DEFAULT CHARSET=latin1 AUTO_INCREMENT=31717 ;

现在

cat10 is postcode

cat8 is Latitude

cat9 is Longitude

我能够计算距离并在纬度和经度的特定英里范围内得到结果

SELECT cat10, ( 3959 * acos( cos( radians( {$coords['Latitude']} ) ) 
* cos( radians( cat8 ) ) * cos( radians( cat9 ) - radians( {$coords['Longitude']} ) ) 
+ sin( radians( {$coords['Latitude']} ) ) * sin( radians( cat8 ) ) ) ) 
AS distance FROM uk_data 
HAVING distance <= {$radius} ORDER BY distance

$coords = array('Latitude' => "57.149727", 'Longitude' => "-2.094735");
$radius = .5;    
$uk_data_radious = uk_data_radious_test($coords,$radius,$q,$pc);

现在我正在尝试进行完整搜索以获取具有特定邮政编码距离的类别..

SELECT *, ( 3959 * acos( cos( radians( {$coords['Latitude']} ) ) * cos( radians( cat8 ) ) * cos( radians( cat9 ) - radians( {$coords['Longitude']} ) ) + sin( radians( {$coords['Latitude']} ) ) * sin( radians( cat8 ) ) ) ) AS distance 
    FROM uk_data where
        cat1 like :cat OR
        cat2 like :cat OR
        cat3 like :cat OR
        cat4 like :cat OR
        cat5 like :cat OR
        cat6 like :cat OR
        cat7 like :cat
    HAVING distance <= {$radius} 
    ORDER BY distance

但这不起作用。HAVING我知道 Query 中有一个错误，但不知道如何使用3 个参数和 Where 一起处理此查询Postcode Distance and categories

错误

Fatal error: Uncaught exception 'PDOException' with message 'SQLSTATE[42000]: Syntax error
 or access violation: 1064 You have an error in your SQL syntax; check the manual that
 corresponds to your MySQL server version for the right syntax to use near ':cat OR cat2 
like :cat OR cat3 like :cat OR cat4 like :cat OR ' at line 4' in
 D:\Winginx\home\****\public_html\functions.php:365 Stack trace: #0 
D:\Winginx\home\****\public_html\functions.php(365): PDO->query('SELECT *, ( 395...') #1 
D:\Winginx\home\***\public_html\miles_output.php(14): uk_data_radious_test(Array, 0.5, 
'Tool') #2 {main} thrown in D:\Winginx\home\***\public_html\functions.php on line 365
4

2 回答 2

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我终于找到了我的问题的解决方案......但我认为可能有更好的方法来做到这一点......我仍然想在这里分享答案，所以如果有人正在寻找相同的答案可能会得到帮助，是的，如果有人有更好的方法来做到这一点，请建议 thx

这是我在做什么

第一使功能

function distance($lat1, $lon1, $lat2, $lon2, $unit) { //** this to calculate distance in Miles or Km

      $theta = $lon1 - $lon2; 
      $dist = sin(deg2rad($lat1)) * sin(deg2rad($lat2)) +  cos(deg2rad($lat1)) * cos(deg2rad($lat2)) * cos(deg2rad($theta)); 
      $dist = acos($dist); 
      $dist = rad2deg($dist); 
      $miles = $dist * 60 * 1.1515;
      $unit = strtoupper($unit);

      if ($unit == "K") {
        return ($miles * 1.609344); 
      } else if ($unit == "N") {
          return ($miles * 0.8684);
        } else {
            return $miles;
          }
    }


        function uk_data_radious($coords, $radius){//** this to get result within certain radios for a postcode
        global $DBH;
        $STH = $DBH->prepare("SELECT DISTINCT cat10, ( 3959 * acos( cos( radians({$coords['Latitude']}) ) 
                  * cos( radians( cat8 ) ) 
                  * cos( radians( cat9 ) - radians({$coords['Longitude']}) ) 
                  + sin( radians({$coords['Latitude']}) ) 
                  * sin( radians( cat8 ) ) )) AS distance FROM uk_data HAVING distance <= {$radius} ORDER BY distance");
        $STH->bindValue(':postcode', "$postcode", PDO::PARAM_STR);
        $STH->setFetchMode(PDO::FETCH_ASSOC);
        $STH->execute();
        return $STH;
    }

        function uk_data_pc_count($user_count){//*** this is to check if post code is in our database or not 
        global $DBH;
        $STH = $DBH->prepare("SELECT * from uk_data where cat10 = :user_count");
        $STH->bindValue(':user_count', $user_count, PDO::PARAM_STR);
        $STH->execute();
        $row_count = $STH ->rowCount();
        return $row_count ;
    }

function comp_post_code($cat, $comp_post_code){//** this to get result within postcode
    global $DBH;
    $STH = $DBH->prepare("SELECT * from uk_data where 
                            cat10 like :comp_post_code  AND (
                            cat1 like :cat OR
                            cat2 like :cat OR
                            cat3 like :cat OR
                            cat4 like :cat OR
                            cat5 like :cat OR
                            cat6 like :cat OR
                            cat7 like :cat OR
                            cat8 like :cat OR
                            cat9 like :cat 
                            )") ;
    $STH->bindValue(':cat', "%$cat%", PDO::PARAM_STR);
    $STH->bindValue(':comp_post_code', "$comp_post_code%", PDO::PARAM_STR);
    $STH->execute();
    $STH->setFetchMode(PDO::FETCH_ASSOC);
    return $STH;
    }

现在在页面上使用它

$q = $_GET['id'];
$pc =  change_text(' ', '',$_GET['pc']);
$qu = change_text(' ', '%', $q);
$pc_o = array();
$comp_name = array();
$comp_phone = array();
$distance = array();
$Latitude = array();
$Longitude = array();
$post_code = array();

if(uk_data_pc_count($pc) > 0  ){

$uk_data_ll = uk_data_ll($pc);
while (($row = $uk_data_ll->fetch()) !== false) {
$Latitude[] = $row['cat8'];
$Longitude[] = $row['cat9'];

}

$coords = array('Latitude' => "$Latitude[0]", 'Longitude' => "$Longitude[0]");
$radius = 10;

$uk_data_radious = uk_data_radious($coords,$radius,$q);
while (($row = $uk_data_radious->fetch()) !== false) {
    /*echo $row['cat10'].' --- '.$row['distance'].'<br>';*/
    $pc_o[] = $row['cat10'];
    $distance[] = $row['distance'];

}
foreach($pc_o as $pc_o){
$uk_data_radious = comp_post_code($q,$pc_o);
while (($row = $uk_data_radious->fetch()) !== false) {
$comp_name[] = $row['comp_name'];
$comp_phone[] = $row['comp_phone'];
$post_code[] = $row['cat10'];
$distance_m[] = distance($Latitude[0],$Longitude[0],$row['cat8'],$row['cat9'],"M");
}}



for($i=0, $count = count($comp_name);$i<$count;$i++) {
    echo $post_code[$i].' - '.$comp_name[$i].' - '.$comp_phone[$i].' - '.round($distance_m[$i],2).' Miles<br>';
    }
}else {echo 'Wrong Post-Code Selected';}

thx 希望这会有所帮助，并希望得到好的建议；）

于 2013-01-03T05:21:09.963 回答
0

尝试输出错误信息。

我不确定，但我认为您不需要使用 HAVING，只需在 ( OR .. ) 部分周围使用大括号，如下所示：

SELECT *, ( 3959 * acos( cos( radians( {$coords['Latitude']} ) ) * cos( radians( cat8 ) ) * cos( radians( cat9 ) - radians( {$coords['Longitude']} ) ) + sin( radians( {$coords['Latitude']} ) ) * sin( radians( cat8 ) ) ) ) AS distance 
FROM uk_data where
   (
    cat1 like :cat OR
    cat2 like :cat OR
    cat3 like :cat OR
    cat4 like :cat OR
    cat5 like :cat OR
    cat6 like :cat OR
    cat7 like :cat
   ) AND distance <= {$radius} 
ORDER BY distance

附带说明一下，每个类别都有一个包含列的表格是不好的设计。每次添加新类别时，您都需要更改 sql 表结构。

于 2013-01-02T11:26:30.383 回答