9

我需要将信息从php客户端发送到java服务器，但是服务器端没有接收到虽然一个打印语句在服务器上成功执行，客户端的文本无法在服务器端接收。以下是代码：

Java 服务器：

import java.io.BufferedReader;
import java.net.*;
import java.io.*;

public class javaphp2 {
    private static ServerSocket socket;

    private static Socket connection;
    private static String command       = new String();
    private static String responseStr   = new String();

    private static int port = 4309;

    public static void main(String args[])  {
        System.out.println("Signal Server is running.");

        try  {
            socket = new ServerSocket(port);

            while (true)  {
                connection = socket.accept();

                InputStreamReader inputStream = new InputStreamReader(connection.getInputStream());
                DataOutputStream response = new DataOutputStream(connection.getOutputStream());
                BufferedReader input = new BufferedReader(inputStream);

                command = input.readLine();
                //System.out.println("The input is" + command);
                response.writeBytes(responseStr);
                response.flush();
                //response.close();

                System.out.println("Running");
            }
        } catch (IOException e)  {
            System.out.println("Fail!: " + e.toString());
        }

        System.out.println("Closing...");
    }
}

PHP客户端：

#!/usr/local/bin/php -q
<?php
$address = '132.119.90.165';
$port = 4309;

$socket = socket_create(AF_INET, SOCK_STREAM, getprotobyname('tcp'));
socket_connect($socket, $address, $port);

$message = 'Apple';
$len = strlen($message);

$status = socket_sendto($socket, $message, $len, 0, $address, $port);
if($status !== FALSE)
{
    $message = '';
    $next = '';
    while ($next = socket_read($socket, 4096))
    {
        $message .= $next;
    }

    echo $message;
}
else
{
    echo "Failed";
}

socket_close($socket);
?>
4

2 回答 2

8

知道了 ！，

我们需要添加$message = "Apple\n";而不是$message = 'Apple\n';

于 2013-01-02T08:26:18.950 回答
0

尝试在您的消息中添加行尾。

$message = 'Apple\n';

readLine 将始终等待行尾。

于 2013-01-02T07:46:11.830 回答