php - 获取用户在排行榜中的位置？

Question

我正在制作这个游戏排行榜，并试图在这个排行榜中获得特定用户的位置。我试过这个但没有运气：

SELECT SUM(points) as points 
FROM publicpoints 
GROUP BY fk_player_id 
WHERE points > (SELECT SUM(points) as points 
                FROM publicpoints 
                WHERE fk_player_id = $playerid)

我该怎么办？

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我也试过这样，但仍然没有运气，但也许这澄清了我试图完成的事情：

$sql = mysql_query("SELECT SUM(points) mypoints FROM ".$prefix."_publicpoints WHERE fk_player_id=$playerid");
$row = mysql_fetch_assoc($sql);

$mypoints = $row['mypoints'];

$sql = mysql_query("SELECT SUM(points) as points FROM ".$prefix."_publicpoints 
                        WHERE points < $mypoints
                    GROUP BY fk_player_id");
$row = mysql_fetch_assoc($sql);

$rank = mysql_num_rows($sql);

if(!empty($mypoints)){
    $rank = $row['rank']+1;
} else {
    $rank = 0;
}

Answer 1

WHERE子句必须在GROUP BY子句之前，如下所示：

SELECT 
  SUM(points) as points 
FROM publicpoints 
WHERE fk_player_id = $playerid
GROUP BY fk_player_id;

然后你可以使用ORDER BYwithLIMIT来获得一个特定的Points位置：

SELECT 
  SUM(points) as points 
FROM publicpoints 
WHERE fk_player_id = $playerid
GROUP BY fk_player_id
ORDER BY points
LIMIT 1 -- for top 1;

---

更新：要获得比当前用户得分更高的用户数，您可以这样做：

SELECT COUNT(*) AS NumberOfPlayers
FROM
(
    SELECT 
       fk_player_id
    FROM points 
    GROUP BY fk_player_id
    HAVING SUM(points) > (SELECT SUM(points)
                          FROM points 
                          WHERE fk_player_id = 5)
) t;

如果你想获得那些比当前用户得分更高的玩家，你可以这样做：

SELECT 
   fk_player_id
FROM points 
GROUP BY fk_player_id
HAVING SUM(points) > (SELECT SUM(points)
                      FROM points 
                      WHERE fk_player_id = 5);

更新的 SQL Fiddle 演示