4

我有几个Buttons在屏幕上。单击一个休息时，应禁用Button所有其他休息。Buttons有没有办法创建一个方法并设置启用和禁用 allButtons而不是启用和禁用单个Buttons.

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4 回答 4

4

此方法假定按钮位于同一个网格上，它会反转每个按钮的启用状态，但单击的按钮除外。

主窗口.xaml

<Window x:Class="WpfApplication1.MainWindow"
        xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
        xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
        Title="MainWindow" Height="350" Width="525">
    <Grid>
        <Button Content="Button" Height="23" HorizontalAlignment="Left" Margin="10,10,0,0" Name="button1" VerticalAlignment="Top" Width="75" Click="button_Click"  />
        <Button Content="Button" Height="23" HorizontalAlignment="Left" Margin="10,43,0,0" Name="button2" VerticalAlignment="Top" Width="75" Click="button_Click" />
        <Button Content="Button" Height="23" HorizontalAlignment="Left" Margin="10,76,0,0" Name="button3" VerticalAlignment="Top" Width="75" Click="button_Click" />
        <Button Content="Button" Height="23" HorizontalAlignment="Left" Margin="10,109,0,0" Name="button4" VerticalAlignment="Top" Width="75" Click="button_Click" />
        <Button Content="Button" Height="23" HorizontalAlignment="Left" Margin="10,142,0,0" Name="button5" VerticalAlignment="Top" Width="75" Click="button_Click" />
    </Grid>
</Window>

主窗口.xaml.cs

private void button_Click(object sender, RoutedEventArgs e)
{
    Button btn = (Button)sender;
    foreach (FrameworkElement  item in ((Panel)btn.Parent).Children )
    {
        if (item is Button)
        {
            if (btn.Name != item.Name)
                item.IsEnabled = !item.IsEnabled;
        }
    }
}
于 2013-01-01T09:08:43.710 回答
1

编写一种处理所有按钮单击的方法。这是一个例子：

Private Sub ButtonsClick(sender As System.Object, e As System.Windows.RoutedEventArgs) Handles button1.Click ,button2.Click ,button3.Click

button1.IsEnabled = (button1 is sender)
button2.IsEnabled = (button2 is sender)
button3.IsEnabled = (button3 is sender)


End Sub

编辑：我忽略了您不想启用/禁用单个按钮的事实。所以我会推荐马克回答。

于 2013-01-01T09:12:51.113 回答
0

我有一个想法，首先创建一个禁用所有按钮的方法。每当单击任何按钮时首先调用该方法，以便禁用所有按钮，然后为该单个按钮单击事件处理程序方法启用您刚刚单击的按钮。

于 2013-01-01T08:42:29.837 回答
0

我用 Christian 在评论中提供的链接完成了 Mark Hall 的回答。你可能会喜欢。
按钮无需位于一个 Grid 中或处理其所有单击事件。

在父窗口中处理PreviewMouseLeftButtonDown事件，而不是：

void window_PreviewMouseLeftButtonDown(object sender, MouseEventArgs e)
{
Window win = sender as Window;
if (e.OriginalSource is Button)
{
     Button btn=(Button)e.Source;
     foreach(Button button0 in FindVisualChildren<Button>(win))
     {
        if (btn != button0)
            button0.IsEnable = false;
     }
}
}

它使用以下方法。请参阅按类型查找 WPF 窗口中的所有控件

public static IEnumerable<T> FindVisualChildren<T>(DependencyObject depObj) where T : DependencyObject
{
if (depObj != null)
{
    for (int i = 0; i < VisualTreeHelper.GetChildrenCount(depObj); i++)
    {
        DependencyObject child = VisualTreeHelper.GetChild(depObj, i);
        if (child != null && child is T)
        {
            yield return (T)child;
        }

        foreach (T childOfChild in FindVisualChildren<T>(child))
        {
            yield return childOfChild;
        }
    }
}
}
于 2013-01-01T11:20:59.170 回答