我从我的 rawQuery 中得到重复并遵循 OR 逻辑而不是 AND 逻辑的结果,即当我只想要那些时,我将获得包含“tuxedo”的所有条目以及包含“hotel”的所有条目包含两者。
这是我的方法:
public ArrayList<Integer> getAdvancedResultIDList(String[] search)
{
ArrayList<String> queryList = new ArrayList<String>();
ArrayList<Integer> resultsList = new ArrayList<Integer>();
SQLiteQueryBuilder builder = new SQLiteQueryBuilder();
this.mDB = GamesList.mDBHelper.getDatabase();
Cursor searchCursor = null;
try
{
//TODO:
// for each string in the search array search the whole of searchable table. Check that the results are only of the values that
// contain all the search strings, and add the id of that row to the results ArrayList
for(int i = 0; i < search.length; i++)
{
String query;
String s = '"' + search[i] + '"';
query = "SELECT " + KEY_ID + " FROM "+ SEARCHABLE_TABLE + " WHERE " + SEARCHABLE_TABLE + " MATCH " + s;
queryList.add(query);
}
String[] queryArray = queryList.toArray(new String[queryList.size()]);
String unionQuery = builder.buildUnionQuery(queryArray, KEY_ID + " ASC", null);
searchCursor = this.mDB.rawQuery(unionQuery, null);
int colId = searchCursor.getColumnIndex(KEY_ID);
String resultID;
for(searchCursor.moveToFirst(); !searchCursor.isAfterLast();searchCursor.moveToNext())
{
resultID = searchCursor.getString(colId);
Integer Id = Integer.parseInt(searchCursor.getString(colId));
resultsList.add(Id);
}
searchCursor.close();
}
catch(Exception e)
{
e.printStackTrace();
}
finally
{
try
{
this.mDB.close();
}
catch(Exception e)
{
e.printStackTrace();
}
}
return resultsList;
}
提前致谢,新年快乐!