android - 具有自定义布局的 Android 对话框：返回数据

Question

我在获取数据时遇到问题，用户输入dialog（使用自定义布局）。看代码：

单位.xml：

<?xml version="1.0" encoding="utf-8"?>
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="match_parent"
android:layout_height="match_parent">

<EditText
    android:id="@+id/editText1"
    android:layout_width="wrap_content"
    android:layout_height="wrap_content">
</EditText>
</RelativeLayout>

代码：

    AlertDialog.Builder builder = new AlertDialog.Builder(this);
    LayoutInflater inflater = this.getLayoutInflater();
    builder.setView(inflater.inflate(R.layout.unit, null)); 
    AlertDialog dialog = builder.create();
    dialog.show();

Dialog以我创建的布局打开，但是

    builder.setPositiveButton("Add", new DialogInterface.OnClickListener() {
          @Override
          public void onClick(DialogInterface dialog, int which) {
                        EditText text = (EditText)findViewById(R.id.editText1);
                        Toast.makeText(getApplicationContext(), text.getText(), Toast.LENGTH_SHORT).show();
            dialog.dismiss();
          }

        });

产生运行时错误：java.lang.NullPointerException。哪里有问题？

Answer 1

用这个..

 builder.setPositiveButton("Add", new DialogInterface.OnClickListener() {
      @Override
      public void onClick(DialogInterface dialog, int which) {
                    EditText text = (EditText) dialog.findViewById(R.id.editText1);
                    Toast.makeText(getApplicationContext(), text.getText(), Toast.LENGTH_SHORT).show();
        dialog.dismiss();
      }

    });

Answer 2

找到了：

AlertDialog aDialog = (AlertDialog) dialog;
EditText name = (EditText) aDialog.findViewById(R.id.editText1);