我在 C 中使用 SDL,我试图在按下一个键时让一个字符在屏幕上移动,并在它被释放时停止,但似乎 KEYUP 事件在按键仍然被按住时触发下。如果我删除pressed() 中的KEYUP 部分,字符将在屏幕上滑动,但显然不会自行停止。如果我保留 KEYUP 部分,我必须反复按该键才能在屏幕上移动它们。知道我做错了什么吗?
这是我所拥有的:
...
int done = 0;
while (done==0)
{
pressed();
if (kenter == 1)
{
state = 1;
subscreen();
}
if (kescape == 1)
{
done = 1;
}
if (kup == 1)
{
playery += -2;
}
if (kdown == 1)
{
playery += 2;
}
if (kright == 1)
{
playerx += 2;
}
if (kleft == 1)
{
playerx += - 2;
}
...
int pressed ()
{
SDL_Event keyevent;
while (SDL_PollEvent(&keyevent))
{
switch(keyevent.type)
{
case SDL_KEYDOWN:
switch(keyevent.key.keysym.sym)
{
case SDLK_RETURN:
{
kenter = 1;
break;
}
case SDLK_ESCAPE:
{
kescape = 1;
break;
}
case SDLK_a:
{
ka = 1;
break;
}
case SDLK_s:
{
ks = 1;
break;
}
case SDLK_UP:
{
kup = 1;
break;
}
case SDLK_DOWN:
{
kdown = 1;
break;
}
case SDLK_RIGHT:
{
kright = 1;
break;
}
case SDLK_LEFT:
{
kleft = 1;
break;
}
default:
break;
}
}
switch(keyevent.type)
{
case SDL_KEYUP:
switch(keyevent.key.keysym.sym)
{
case SDLK_RETURN:
{
kenter = 0;
break;
}
case SDLK_ESCAPE:
{
kescape = 0;
break;
}
case SDLK_a:
{
ka = 0;
break;
}
case SDLK_s:
{
ks = 0;
break;
}
case SDLK_UP:
{
kup = 0;
break;
}
case SDLK_DOWN:
{
kdown = 0;
break;
}
case SDLK_RIGHT:
{
kright = 0;
break;
}
case SDLK_LEFT:
{
kleft = 0;
break;
}
default:
break;
}
}
}
return 0;
}