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如何从http://gdata.youtube.com/feeds/api/playlists/EL5BQGc0nPiVI?v=2&alt=json获取视频列表

我已经制作了一个程序,我可以在其中使用这种 URL 获取视频列表:请检查这个,但这次我想在 Android 中使用 Playlist 获取视频列表,就像使用这个URL 一样,实际YouTube 视频网址

在这里,我使用的是 JSON,但现在我不知道我需要对代码进行哪些更改才能使用上述播放列表 URL 获取视频列表。

  @Override
  public void run() {
    try {
        
        HttpClient client = new DefaultHttpClient();
        
        HttpUriRequest request = new HttpGet("http://gdata.youtube.com/feeds/api/playlists/EL5BQGc0nPiVI?v=2&alt=json"); 
    
        // Get the response that YouTube sends back
        HttpResponse response = client.execute(request);
        // Convert this response into a readable string
    String jsonString = StreamUtils.convertToString
            (response.getEntity().getContent());
        // Create a JSON object that we can use from the String
        JSONObject json = new JSONObject(jsonString);
        
        
        
        // Get is search result items
    JSONArray jsonArray = json.getJSONObject("data").getJSONArray("items");
        
        // Create a list to store are videos in
        List<Video> videos = new ArrayList<Video>();
        
        for (int i = 0; i < jsonArray.length(); i++) {
            JSONObject jsonObject = jsonArray.getJSONObject(i);
            // The title of the video
            String title = jsonObject.getString("title");
            
            String url;
            try {
    url = jsonObject.getJSONObject("player").getString("default");
    } catch (JSONException ignore) {
    url = jsonObject.getJSONObject("player").getString("default");
            }
            
            
            String thumbUrl = jsonObject.getJSONObject("thumbnail").getString("sqDefault");
            
            
            videos.add(new Video(title, url, thumbUrl));
        }
        
        Library lib = new Library(username, videos);
        
        Bundle data = new Bundle();
        data.putSerializable(LIBRARY, lib);
        
        Message msg = Message.obtain();
        msg.setData(data);
        replyTo.sendMessage(msg);
    
    } catch (ClientProtocolException e) {
        Log.e("Feck", e);
    } catch (IOException e) {
        Log.e("Feck", e);
    } catch (JSONException e) {
        Log.e("Feck", e);
    }
}
4

2 回答 2

1
 String JKYouTubeActivity.YOUTUBE_INFO_URL=http://gdata.youtube.com/feeds/api/playlists/_ID_?v=2&alt=json

 private String getUrl(String id) throws IOException, JSONException {
        HttpClient client = new DefaultHttpClient();
        HttpGet clientGetMethod = new HttpGet(JKYouTubeActivity.YOUTUBE_INFO_URL.replace("_ID_", id));
        HttpResponse clientResponse = null;
        clientResponse = client.execute(clientGetMethod);
        String infoString = _convertStreamToString(clientResponse.getEntity().getContent());
        String urldata=new JSONObject(infoString).getJSONObject("entry").getJSONObject("media$group").getJSONArray("media$content").getJSONObject(0).getString("url");
        return new JSONObject(infoString).getJSONObject("entry").getJSONObject("media$group").getJSONArray("media$content").getJSONObject(0).getString("url");
    }

    private String _convertStreamToString(InputStream iS) {
        BufferedReader reader = new BufferedReader(new InputStreamReader(iS));
        StringBuilder sB = new StringBuilder();
        String line = null;
        try {
            while ((line = reader.readLine()) != null)
            {
                sB.append(line).append("\n");
            }
        } catch (IOException e) {
            e.printStackTrace();
        } finally {
            try {
                iS.close();
            } catch (IOException e) {
                e.printStackTrace();
            }
        }
        return sB.toString();
    }

}

获取 urldata 后,您可以对其进行流式传输或做任何您想做的事情。同样,您也可以获得缩略图和标题

于 2012-12-31T09:52:18.883 回答
0

您可以使用 recyclerView 作为列表。我已经使用 Youtube api 休息调用完成了这项工作。您需要从谷歌开发者控制台获取浏览器密钥。我在这里的回答中解释了这一点:

https://stackoverflow.com/a/41201084/3689744

Youtube 休息调用的“新方式”将如下所示(我相信最大结果是 50):

https://www.googleapis.com/youtube/v3/playlistItems?part=snippet&playlistId=iBi9LVIrC-fVelw2-I2r-yrEk6SpXfO8&key=AIzaSyCI1oCTXwZzgVv7LDQ8NykSIUEWt247KnU&maxResults=50

于 2016-12-17T10:05:07.127 回答