mysql - 查询不等于多个值

Question

我有一点编码，有人可以帮助我使查询正确，我以为我有它，但我只是收到一个查询错误
原始代码：

$q=$db->query("SELECT u.*,g.* FROM users u LEFT JOIN gangs g ON g.gangID=u.gang WHERE u.user_level != 2 $myf ORDER BY level DESC,userid ASC LIMIT 20");

我失败的编辑代码：

$q=$db->query("SELECT u.*,g.* FROM users u LEFT JOIN gangs g ON g.gangID=u.gang WHERE u.user_level != 2 || WHERE u.user_level !=0 $myf ORDER BY level DESC,userid ASC LIMIT 20");

Answer 1

用这个

$q=$db->query("SELECT u.*,g.* FROM users u LEFT JOIN gangs g ON g.gangID=u.gang WHERE u.user_level != 2 || u.user_level !=0 $myf ORDER BY level DESC,userid ASC LIMIT 20");

你不能放两个 where 子句

仅供参考：http ://dev.mysql.com/doc/refman/5.0/en//select.html

Answer 2

反而

$q=$db->query("SELECT u.*,g.* FROM users u LEFT JOIN gangs g ON g.gangID=u.gang WHERE u.user_level != 2 || WHERE u.user_level !=0 $myf ORDER BY level DESC,userid ASC LIMIT 20");

你应该，（删除第二个位置）

$q=$db->query("SELECT u.*,g.* FROM users u LEFT JOIN gangs g ON g.gangID=u.gang WHERE u.user_level != 2 || u.user_level !=0 $myf ORDER BY level DESC,userid ASC LIMIT 20");