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我想模拟许多按键事件。我通过使用找到了解决方案XTestFakeKeyEvent,但是当我模拟超过 210 次时,我的程序引发了“达到的最大客户端数”分段错误。我不知道如何解决这个问题。

我的代码在这里:

#include <X11/Xlib.h>
#include <X11/keysym.h>
#include <X11/extensions/XTest.h>
#include <stdio.h>

#define PRESS_UP    0
#define PRESS_DOWN  1
#define PRESS_LEFT  2
#define PRESS_RIGHT 3
#define PRESS_ENTER 4
#define PRESS_ESC   5
#define PRESS_HOME  6

 Display *display;
 unsigned int keycode;

 int press(int key){
    display = XOpenDisplay(NULL);

    if(key == PRESS_UP)
        keycode = XKeysymToKeycode(display, XK_Up);
    else if(key == PRESS_DOWN)
        keycode = XKeysymToKeycode(display, XK_Down);
    else if(key == PRESS_LEFT)
        keycode = XKeysymToKeycode(display, XK_Left);
    else if(key == PRESS_RIGHT)
        keycode = XKeysymToKeycode(display, XK_Right);
    else if(key == PRESS_ENTER)
        keycode = XKeysymToKeycode(display, XK_Return);
    else if(key == PRESS_ESC)
        keycode = XKeysymToKeycode(display, XK_Escape);
    else if(key == PRESS_HOME)
        keycode = XKeysymToKeycode(display, XK_Home);

    XTestFakeKeyEvent(display, keycode, True, 0);
    XTestFakeKeyEvent(display, keycode, False, 0);
    XFlush(display);
    return 0;
}

int main(int argc, char *argv[]){
    int count = 0;
    while (count < 500){
        press(PRESS_UP);
        printf("count =%d\n" ,count);
        count ++;
    }
}

输出 :

$ gcc -lXtst -lX11 Util_KeyPressSimulator.c 
$ ./a.out 
count =0
^[[Acount =1
^[[Acount =2
...
^[[Acount =208
^[[Acount =209
^[[Acount =210
^[[AMaximum number of clients reachedSegmentation fault

请哪位帮忙,谢谢。

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1 回答 1

12

您正在执行XOpenDisplay没有匹配的每次迭代XCloseDisplay。考虑main()在循环内、循环外打开一次显示,然后在退出前关闭它。

于 2009-09-11T09:19:26.783 回答