25

我的类别有一个表，每个类别都有 id、name 和 parent_id。

Select IF(a.parent_id IS NULL, a.name, CONCAT((SELECT b.name FROM category b WHERE b.id = a.parent_id), " / ", a.name) ) as n, a.id, a.parent_id
FROM category a
ORDER BY n

我想把它转换成我的 Doctrine2 Query Builder

    $em = $this->getDoctrine()->getEntityManager();
    $qb = $em->createQueryBuilder();
    $q = $qb
            ->select("c.id")
            ->addSelect(
                "IF(c.parent_id IS NULL, c.name, CONCAT((" .
                $em->createQueryBuilder()
                   ->select("t.name")
                   ->from("MyBundle:Category", "t")
                   ->getQuery()->getDQL() .
                "), \" / \", c.name) )"
            )
            ->from("MyBundle:Category", "c");
    echo $q->getQuery()->getSQL();
    exit;

类似的东西，但我不能使用IF, 和CONCAT.

4

3 回答 3

58

好的，我找到了解决方案。

您可以使用CASE而不是IF. 看看这个，但是当我使用我的字段时，CASE我不能：CONCAT

$em = $this->getDoctrine()->getEntityManager();
$qb = $em->createQueryBuilder();
$q = $qb
      ->select("c.id")
      ->addSelect("CASE WHEN (c.parent IS NULL) THEN c.name ELSE 'something' END")
      ->from("MyBundle:Category", "c")
      ->leftJoin("c.parent", "t");

echo $q->getQuery()->getSQL();

另一个解决方案是创建自己的 DQL 函数，像这样IF使用它：

$em = $this->getDoctrine()->getEntityManager();
$qb = $em->createQueryBuilder();
$q = $qb
      ->select("c.id")
      ->addSelect("IF(c.parent IS NULL, c.name, CONCAT(CONCAT(t.name, ' / '), c.name))")
      ->from("MyBundle:Category", "c")
      ->leftJoin("c.parent", "t");

echo $q->getQuery()->getSQL();

要创建此 IF，您可以访问此链接并学习：http ://docs.doctrine-project.org/projects/doctrine-orm/en/latest/reference/dql-doctrine-query-language.html#adding-your -自己的功能到 dql 语言

我将在这里发布我的 IF 课程和 config.yml 以帮助其他人。这是 IfFunction 类（我从https://github.com/beberlei/DoctrineExtensions/blob/master/src/Query/Mysql/IfElse.php获得）：

<?php
namespace MyName\MiscBundle\Doctrine\ORM\Query\AST\Functions;

use Doctrine\ORM\Query\AST\Functions\FunctionNode;
use Doctrine\ORM\Query\Lexer;

/**
 * Usage: IF(expr1, expr2, expr3)
 * 
 * If expr1 is TRUE (expr1 <> 0 and expr1 <> NULL) then IF() returns expr2;
 * otherwise it returns expr3. IF() returns a numeric or string value,
 * depending on the context in which it is used. 
 * 
 * @author  Andrew Mackrodt <andrew@ajmm.org>
 * @version 2011.06.19
 */
class IfFunction extends FunctionNode
{
    private $expr = array();

    public function parse(\Doctrine\ORM\Query\Parser $parser)
    {
        $parser->match(Lexer::T_IDENTIFIER);
        $parser->match(Lexer::T_OPEN_PARENTHESIS);
        $this->expr[] = $parser->ConditionalExpression();

        for ($i = 0; $i < 2; $i++)
        {
            $parser->match(Lexer::T_COMMA);
            $this->expr[] = $parser->ArithmeticExpression();
        }

        $parser->match(Lexer::T_CLOSE_PARENTHESIS);
    }

    public function getSql(\Doctrine\ORM\Query\SqlWalker $sqlWalker)
    {
        return sprintf('IF(%s, %s, %s)',
            $sqlWalker->walkConditionalExpression($this->expr[0]),
            $sqlWalker->walkArithmeticPrimary($this->expr[1]),
            $sqlWalker->walkArithmeticPrimary($this->expr[2]));
    }
}

之后，您需要像这样更新您的 config.yml（刚刚添加了最后 3 行）：

doctrine:
    dbal:
        driver:   "%database_driver%"
        host:     "%database_host%"
        port:     "%database_port%"
        dbname:   "%database_name%"
        user:     "%database_user%"
        password: "%database_password%"
        charset:  UTF8

    orm:
        auto_generate_proxy_classes: "%kernel.debug%"
        auto_mapping: true
        dql: #ADDED THIS LINE
            string_functions: #ADDED THIS LINE
                IF: MyName\MiscBundle\Doctrine\ORM\Query\AST\Functions\IfFunction #ADDED THIS LINE

谢谢

于 2013-01-01T01:41:05.653 回答
2

您还可以结合CASE和CONCAT：

$q = $this->createQueryBuilder('a')
    ->select('a.id')
    ->addSelect('CASE WHEN(a.parent IS NULL) THEN \'\' else CONCAT(:variable, a.name, \'string\') END as name')
    ->setParameter('variable', $variable)
    ... ;
于 2015-08-03T12:42:14.177 回答
0

假设您在 Category 中有一个名为“parent”的关系，这会更好吗？：

$em = $this->getDoctrine()->getEntityManager();
$qb = $em->createQueryBuilder();
$q  = $qb
      ->select("c.id")
   ->addSelect("IF (c.parent_id IS NULL, c.name, CONCAT(t.name, ' / ', c.name))"
        ->from("MyBundle:Category", "c")
    ->leftJoin("c.parent t"));

echo $q->getQuery()->getSQL();
于 2012-12-31T09:53:10.810 回答