ruby-on-rails - Mongoid 排除所有带有 :state of "this" OR "that" 的记录？

Question

Model.excludes(state: "this).excludes(state: "that")

产生：

"state"=>{"$ne"=>"that"}

但我真正想要的是排除所有具有“this”或“that”的记录

Answer 1

这是一个使用 Model.not_in 的工作测试

http://two.mongoid.org/docs/querying/criteria.html#not_in

应用程序/模型/model.rb

class Model
  include Mongoid::Document
  field :state, type: String
end

测试/单元/model_test.rb：

require 'test_helper'

class ModelTest < ActiveSupport::TestCase
  def setup
    Model.delete_all
  end

  test "not_in" do
    Model.create({ state: 'this' })
    Model.create({ state: 'that' })
    Model.create({ state: 'not this or that'})
    assert_equal(3, Model.count)
    p Model.not_in(state: ['this', 'that']).to_a
    assert_equal(1, Model.not_in(state: ['this', 'that']).to_a.count)
  end
end

耙式测试：

Run options:

# Running tests:

[#<Model _id: 50e6fdef29daeb27e5000003, _type: nil, state: "not this or that">]
.

Finished tests in 0.021175s, 47.2255 tests/s, 94.4510 assertions/s.

1 tests, 2 assertions, 0 failures, 0 errors, 0 skips