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我是 Android 开发的初学者。我想制作一个 android 应用程序,它将 GPS 和网络位置(纬度和经度)发送到我的服务器(静态 IP)。我找到了以下代码并且它成功运行,在服务器端已经制作的应用程序接收数据(现在它与客户端应用程序无关)

当我在我的 Android 应用程序上单击“发送位置”按钮时,我的服务器收到的数据。

  • 获取 /31.4244456/74.7349772 HTTP/1.1

  • 主机:180.178.169.77:6081

  • 连接:保持活动状态

  • 用户代理:Apache-HttpClient/不可用(java 1.4)

180.178.169.77是我的服务器IP,6081是端口

此时一切正常,我几乎实现了我想要的,但我面临的真正问题是我的 Android 应用程序在将此数据发送到服务器后挂起并崩溃。如果有人有想法,请解决我的问题。

我从这里找到了代码。 http://www.gideondsouza.com/blog/how-to-get-the-current-location-address-and-send-it-to-a-server-on-android#.UNLbTOT0Dxo

这是我的 AddressActivity.java

package com.gideon.address;

import java.io.IOException;
import java.util.List;
import java.util.Locale;

import org.apache.http.HttpResponse;
import org.apache.http.client.ClientProtocolException;
import org.apache.http.client.HttpClient;
import org.apache.http.client.methods.HttpGet;
import org.apache.http.impl.client.DefaultHttpClient;
import android.app.Activity;
import android.content.Context;
import android.location.Address;
import android.location.Geocoder;
import android.location.Location;
import android.location.LocationListener;
import android.location.LocationManager;
import android.os.Bundle;
import android.view.View;
import android.view.View.OnClickListener;
import android.widget.Button;
import android.widget.TextView;
import android.widget.Toast;


public class AddressActivity extends Activity {
/** Called when the activity is first created. */
String lat="", lon="";

@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.main);

    Button btnLocation = (Button)findViewById(R.id.btnLocation);
    btnLocation.setOnClickListener(new OnClickListener() {
        public void onClick(View arg0) {
            // Acquire a reference to the system Location Manager
            LocationManager locationManager = (LocationManager) AddressActivity.this.getSystemService(Context.LOCATION_SERVICE);
            // Define a listener that responds to location updates
            LocationListener locationListener = new LocationListener() {
                public void onLocationChanged(Location location) {
                    // Called when a new location is found by the network location provider.
                    lat = Double.toString(location.getLatitude());
                    lon = Double.toString(location.getLongitude());
                    TextView tv = (TextView) findViewById(R.id.txtLoc);
                    tv.setText("Your Location is:" + lat + "--" + lon);
                }

                public void onStatusChanged(String provider, int status, Bundle extras) {}
                public void onProviderEnabled(String provider) {}
                public void onProviderDisabled(String provider) {}
            };
            // Register the listener with the Location Manager to receive location updates
            locationManager.requestLocationUpdates(LocationManager.NETWORK_PROVIDER, 0, 0, locationListener);
        }
    });

    Button btnSend = (Button)findViewById(R.id.btnSend);
    btnSend.setOnClickListener(new OnClickListener() {
        public void onClick(View v) {
            postData(lat, lon);
        }
    });

    Button btnAdd = (Button)findViewById(R.id.btnAddress);
    btnAdd.setOnClickListener(new OnClickListener() {
        public void onClick(View v) {
            TextView tv = (TextView)findViewById(R.id.txtAddress);
            tv.setText(GetAddress(lat, lon));
        }
    });

}

public void postData(String la, String lo) {
    // Create a new HttpClient and Post Header
    HttpClient httpclient = new DefaultHttpClient();
    //HttpGet  htget = new HttpGet("http://myappurl.com/Home/Book/"+la+"/"+lo);
    HttpGet  htget = new HttpGet("http://180.178.169.77:6081/"+la+"/"+lo);

    try {
        // Execute HTTP Post Request
        HttpResponse response = httpclient.execute(htget);
        String resp = response.getStatusLine().toString();
        Toast.makeText(this, resp, 5000).show();


    } catch (ClientProtocolException e) {
        Toast.makeText(this, "Error", 5000).show();
    } catch (IOException e) {
        Toast.makeText(this, "Error", 5000).show();
    }
} 
public String GetAddress(String lat, String lon)
{
    Geocoder geocoder = new Geocoder(this, Locale.ENGLISH);
    String ret = "";
    try {
        List<Address> addresses = geocoder.getFromLocation(Double.parseDouble(lat), Double.parseDouble(lon), 1);
        if(addresses != null) {
            Address returnedAddress = addresses.get(0);
            StringBuilder strReturnedAddress = new StringBuilder("Address:\n");
            for(int i=0; i<returnedAddress.getMaxAddressLineIndex(); i++) {
                strReturnedAddress.append(returnedAddress.getAddressLine(i)).append("\n");
            }
            ret = strReturnedAddress.toString();
        }
        else{
            ret = "No Address returned!";
        }
    } catch (IOException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
        ret = "Can't get Address!";
    }
    return ret;
}
}

这是我的 AndroidManifest.xml

<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
    package="com.gideon.address"
    android:versionCode="1"
    android:versionName="1.0" >

    <uses-sdk android:minSdkVersion="8" />
    <uses-permission android:name="android.permission.ACCESS_COARSE_LOCATION"/>
    <uses-permission android:name="android.permission.INTERNET"/>
    <application
        android:icon="@drawable/ic_launcher"
        android:label="@string/app_name" >
        <activity
            android:name=".AddressActivity"
            android:label="@string/app_name" >
            <intent-filter>
                <action android:name="android.intent.action.MAIN" />

                <category android:name="android.intent.category.LAUNCHER" />
            </intent-filter>
        </activity>
    </application>

</manifest>
4

2 回答 2

2

postData主线程移到辅助线程。在这里查看Async任务示例:http: //developer.android.com/reference/android/os/AsyncTask.html

于 2012-12-30T03:42:42.423 回答
0

你的问题是

 public void onClick(View v) {
            postData(lat, lon);
        }

在 UI 线程上运行。这意味着当您执行“发布”操作时,UI 不会刷新并且无法访问 - 您的应用会卡住,直到发布结束。

您需要执行以下操作:

  public void onClick(View v) {
        PostAsyncTask postAsyncTask = new PostAsyncTask();
        postAsyncTask.execute();
    }



 private class PostAsyncTask extends AsyncTask<URL, Integer, Long> {
 protected Long doInBackground(URL... urls) {
     postData(lat, lon);
     return 0;
 }

 protected void onPreExecute() {
     // show progress dialog
 }


     protected void onPostExecute(Long result) {
         // hide  progress dialog
     }
 }
于 2012-12-30T07:22:48.463 回答