我想从一个NSDictionary
一次 10 个,所以 objectAtIndex 0 到 9
现在只添加:
AddObject:[[[json objectForKey:@"one"] objectAtIndex:1] ObjectForKey:@"likes"];
那9次,有没有更简单的方法可以做到这一点,并且只在对象存在时添加。
提前致谢
我想从一个NSDictionary
一次 10 个,所以 objectAtIndex 0 到 9
现在只添加:
AddObject:[[[json objectForKey:@"one"] objectAtIndex:1] ObjectForKey:@"likes"];
那9次,有没有更简单的方法可以做到这一点,并且只在对象存在时添加。
提前致谢
试试这个:
NSArray *shotsArr = [json objectForKey:@"shots"];
NSMutableArray *allViewsCounts = [NSMutableArray array];
for (NSDictionary *shotDict in shotsArr) {
NSNumber *viewsCount = [shotDict objectForKey:@"views_count"];
[allViewsCounts addObject:viewsCount];
}
如果您希望此数组中只有 10 个对象:
__block NSMutableArray *allViewsCounts = [NSMutableArray array];
[shotsArr enumerateObjectsUsingBlock:^(id obj, NSUInteger idx, BOOL *stop) {
NSDictionary *shotDict = obj;
NSNumber *viewsCount = [shotDict objectForKey:@"views_count"];
[allViewsCounts addObject:viewsCount];
if (idx == 10) {
*stop = YES;
}
}];
简单地使用 for 循环
for (int i=0;i<10;i++){
if([[[json objectForKey:@"one"] objectAtIndex:i] ObjectForKey:@"likes"]){
AddObject:[[[json objectForKey:@"one"] objectAtIndex:i] ObjectForKey:@"likes"];
}
}