linux - 我在哪里可以找到函数 argp_parse 的源代码？

Question

我需要函数的 GNU Linux 代码

    error_t argp_parse(const struct argp *__restrict __argp,int,char **__restrict,unsigned     __flags,int * __arg_index,void *__restrict input)

如果有人知道在哪里可以得到或拥有它，请发给我。非常感谢 ！！

Answer 1

glibc 的一部分，通过 gnu.org 上的链接很容易找到：

来自http://sourceware.org/git/?p=glibc.git;a=blob_plain;f=argp/argp-parse.c;hb=e07bb02a4f9e7d98f79f428a661c5b982286869d：

/* Parse the options strings in ARGC & ARGV according to the argp in ARGP.
   FLAGS is one of the ARGP_ flags above.  If END_INDEX is non-NULL, the
   index in ARGV of the first unparsed option is returned in it.  If an
   unknown option is present, EINVAL is returned; if some parser routine
   returned a non-zero value, it is returned; otherwise 0 is returned.  */
error_t
__argp_parse (const struct argp *argp, int argc, char **argv, unsigned flags,
      int *end_index, void *input)
{
  error_t err;
  struct parser parser;
…