0

我有一种情况，用户点击特定按钮，我的应用程序中会显示一个以对话框为主题的活动。由于第二个活动（对话框活动）的内容是使用HttpRequest我希望用户看到的，ProgressDialog直到加载对话框。

AsyncTask 似乎是用于此目的的最佳选择。因此，我编写了以下课程。

public class DetailsList extends AsyncTask<String, Integer, String> {

public static final String LOG_TAG = "DetailsList";
private Context context;
private ProgressDialog dialog;
private Activity activity;

public DetailsList(Context context) {
    this.context = context;
}

public DetailsList(Activity activity) {
    this.activity = activity;
}

@Override
protected void onPreExecute() {
    dialog = new ProgressDialog(this.context);
    dialog.setMessage("Loading...");
    dialog.setCanceledOnTouchOutside(false);
}

@Override
protected void onPostExecute(String result) {
    if(dialog.isShowing()) {
        dialog.dismiss();
    }
}

@Override
protected String doInBackground(String...params) {
    this.publishProgress(100);
    Log.d(LOG_TAG, "doInBackground started.");
    JSONObject requestContent = new JSONObject();
    JSONObject detailViewResponse = new JSONObject();
    try {
        requestContent.put("serviceId", params[0]);
        APIRequest detailViewAPI = new APIRequest(
                "http://" + GeneralConstants.SERVER_ADDRESS + "/services/",
                requestContent
                );
        detailViewResponse = detailViewAPI.request();
    } catch (Exception e) {
        e.printStackTrace();
    }
    return detailViewResponse.toString();
}

@Override
protected void onProgressUpdate(Integer... values) {
    super.onProgressUpdate(values);
    dialog.show();
}

}

当进行 get 调用时，我有以下异常堆栈跟踪：

12-29 05:12:29.149: W/System.err(3459): java.lang.RuntimeException: Can't create handler inside thread that has not called Looper.prepare()
12-29 05:12:29.159: W/System.err(3459):     at android.os.Handler.<init>(Handler.java:121)
12-29 05:12:29.159: W/System.err(3459):     at android.app.Dialog.<init>(Dialog.java:112)
12-29 05:12:29.159: W/System.err(3459):     at android.app.AlertDialog.<init>(AlertDialog.java:114)
12-29 05:12:29.159: W/System.err(3459):     at android.app.AlertDialog.<init>(AlertDialog.java:98)
12-29 05:12:29.164: W/System.err(3459):     at android.app.ProgressDialog.<init>(ProgressDialog.java:77)
12-29 05:12:29.164: W/System.err(3459):     at threads.DetailsList.<init>(DetailsList.java:30)
12-29 05:12:29.164: W/System.err(3459):     at app.command.DetailViewDisplayCommand.execute(DetailViewDisplayCommand.java:54)
12-29 05:12:29.164: W/System.err(3459):     at commands.Command.execute(Command.java:32)
12-29 05:12:29.164: W/System.err(3459):     at gl.ObjectPicker.findObjectForValue(ObjectPicker.java:92)
12-29 05:12:29.164: W/System.err(3459):     at gl.ObjectPicker.pickObject(ObjectPicker.java:58)
12-29 05:12:29.164: W/System.err(3459):     at gl.GL1Renderer.onDrawFrame(GL1Renderer.java:111)
12-29 05:12:29.164: W/System.err(3459):     at android.opengl.GLSurfaceView$GLThread.guardedRun(GLSurfaceView.java:1520)
12-29 05:12:29.164: W/System.err(3459):     at android.opengl.GLSurfaceView$GLThread.run(GLSurfaceView.java:1244)

似乎错误是从我初始化对话框的行触发的。

dialog = new ProgressDialog(this.context);
4

1 回答 1

3 
at android.opengl.GLSurfaceView$GLThread.run(GLSurfaceView.java:1244)

AsyncTask 旨在防止主线程因繁重的操作而变慢。但是，您不在主线程上，而是在 OpenGL 线程上。我自己没有尝试过，但是会发生什么：

@Override
protected void onPreExecute() {
    Looper.prepare();
    Looper.loop();
    dialog = new ProgressDialog(this.context);
    dialog.setMessage("Loading...");
    dialog.setCanceledOnTouchOutside(false);
}

@Override
protected void onPostExecute(String result) {
    if(dialog.isShowing()) {
        dialog.dismiss();
    }
    Looper.quit();
}

（这可能有效，也可能会尝试从错误的线程异常访问 UI。）

于 2012-12-29T00:29:18.973 回答