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我有一个实现 ISerializable 的类 X

#region ISerializable Members

    /// <summary>
    /// Sets up for deserialization
    /// </summary>
    /// <param name="info"></param>
    /// <param name="context"></param>
    private X(SerializationInfo info, StreamingContext context)
    {
        this.Key = info.GetString("Key");
        this.Title = info.GetString("Title");
        this.Count = info.GetInt32("Count");

        originalDataSource = new ObservableDataSource<IDataType>((IDataType[])info.GetValue("DataSource", typeof(IDataType[])));

        this.A = (Color)ColorConverter.ConvertFromString(info.GetString("A"));
        this.B = Utilities.GetDashStyleFromString(info.GetString("B"));
        this.C = info.GetDouble("C");
        this.D = (Color)ColorConverter.ConvertFromString(info.GetString("D"));
        this.E = (Shape)Enum.Parse(typeof(Shape), info.GetString("E"));
        this.F = info.GetInt32("F");
        this.G = info.GetInt32("G");
        this.H = info.GetInt32("H");
        this.I = info.GetBoolean("I");
    }

    /// <summary>
    /// Sets up for serialization
    /// </summary>
    /// <param name="info"></param>
    /// <param name="context"></param>
    [SecurityPermissionAttribute(SecurityAction.Demand, SerializationFormatter = true)]
    public void GetObjectData(SerializationInfo info, StreamingContext context)
    {
        info.AddValue("Key", this.Key);
        info.AddValue("Title", this.Title);
        info.AddValue("Count", this.Count);

        info.AddValue("DataSource", this.originalDataSource.Collection.ToArray<IDataType>());

        info.AddValue("A", this.A.ToString());
        info.AddValue("B", this.B.ToString());
        info.AddValue("C", this.C);
        info.AddValue("D", this.D.ToString());
        info.AddValue("E", this.E);
        info.AddValue("F", this.F);

        info.AddValue("G", this.G);
        info.AddValue("H", this.H);
        info.AddValue("I", this.I);
    }

    #endregion

我有一个 Y 类,其中包含一个 List 和一个 eventtaggregator。

#region ISerializable Members

    /// <summary>
    /// Sets up for deserialization
    /// </summary>
    /// <param name="info"></param>
    /// <param name="context"></param>
    private Y(SerializationInfo info, StreamingContext context)
    {
        List<X> Coll = (List<X>)info.GetValue("DataSource", typeof(List<X>));

        if (_Collection == null)
            _Collection = new List<X>();

        foreach (X x in Coll)
            _Collection.Add(x);

        Count = info.GetInt32("Count");
    }

    /// <summary>
    /// Sets up for serialization
    /// </summary>
    /// <param name="info"></param>
    /// <param name="context"></param>
    [SecurityPermissionAttribute(SecurityAction.Demand, SerializationFormatter = true)]
    public void GetObjectData(SerializationInfo info, StreamingContext context)
    {
        info.AddValue("DataSource", _Collection);
        info.AddValue("Count", this.Count);
    }

    #endregion

我需要以二进制序列化 Y 。

但是当我反序列化 Y 并检查以下行时,它会返回一个带有空值的 List,而不是应该已序列化的 X 对象。

List<X> Coll = (List<X>)info.GetValue("DataSource", typeof(List<X>));

知道这段代码有什么问题吗?我无法简单地使用条件序列化进行序列化,Color 没有被序列化,而且 ObservableDataSource 没有 Serializable 属性,我无法修改它。

这是在 .NET 框架 3.5 中(如果有任何用处)。

4

1 回答 1

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Color 类不可序列化,您必须为它实现自己的自定义序列化格式(我通常会序列化 ARGB 代码)。

除此之外,BinarySerializer 支持集合序列化,因此您实际上不需要实现自己的序列化函数。

于 2012-12-28T11:27:13.283 回答