3

我有以下查询：

    SELECT
    Test_Case_Name,
    Test_Case_Description,
    Test_Case_Status,
CASE WHEN Test_Case_Status = 'FAILED' THEN
    LISTAGG(LN.LN_BUG_ID,', ') WITHIN GROUP(ORDER BY LN.LN_BUG_ID)
END AS Defect_ID
FROM Test LEFT JOIN LINK LN ON
    LN.LN_ENTITY_ID=Test.TS_TEST_ID
GROUP BY
    Test_Case_Name,
    Test_Case_Description,
    Test_Case_Status

当我运行这个查询时，我得到了错误

ORA-00932: 不一致的数据类型预期得到 CLOB

这是因为该列Test_Case_Description是一种CLOB数据类型。如果我从 select 子句中评论此列，它可以正常工作，但我需要在输出中使用此列。

上面的查询是这里原始查询的简化版

4

2 回答 2

3

以下是您可能要用于您的要求的语法：

句法：

DBMS_LOB.SUBSTR (lob_loc, amount, offset)

Parameter Description 
lob_loc: Locator for the LOB to be read i.e CLOB column name. 
amount: Number of bytes (for BLOBs) or characters (for CLOBs) to be read. 
offset: Offset in bytes (for BLOBs) or characters (for CLOBs) from the start of the LOB (origin: 1).

所以你的最终查询应该是这样的，

    SELECT
    Test_Case_Name,
    DBMS_LOB.SUBSTR(Test_Case_Description,2000,1) as Test_Case_Description,
    Test_Case_Status,
CASE WHEN Test_Case_Status = 'FAILED' THEN
    LISTAGG(LN.LN_BUG_ID,', ') WITHIN GROUP(ORDER BY LN.LN_BUG_ID)
END AS Defect_ID
FROM Test LEFT JOIN LINK LN ON
    LN.LN_ENTITY_ID=Test.TS_TEST_ID
GROUP BY
    Test_Case_Name,
    Test_Case_Description,
    Test_Case_Status

由于您担心在 4000 个字符后不会丢失数据，我的建议是划分列并显示如下..

SELECT
    Test_Case_Name,
    DBMS_LOB.SUBSTR(Test_Case_Description,4000,1) as Test_Case_Description1,
    DBMS_LOB.SUBSTR(Test_Case_Description,8000,4001) as Test_Case_Description2
    Test_Case_Status,
CASE WHEN Test_Case_Status = 'FAILED' THEN
    LISTAGG(LN.LN_BUG_ID,', ') WITHIN GROUP(ORDER BY LN.LN_BUG_ID)
END AS Defect_ID
FROM Test LEFT JOIN LINK LN ON
    LN.LN_ENTITY_ID=Test.TS_TEST_ID
GROUP BY
    Test_Case_Name,
    Test_Case_Description1,
    Test_Case_Description2,
    Test_Case_Status
于 2012-12-25T18:54:08.667 回答
2

我刚刚将我的查询更改为如下所述并且它有效：

SELECT 
    InnerTable.Test_Case_Name,
    Test.Test_Case_Description,
    InnerTable.Test_Case_Status,
FROM 
    (   SELECT
    Test_Case_ID
    Test_Case_Name,
    Test_Case_Status,
CASE WHEN Test_Case_Status = 'FAILED' THEN
    LISTAGG(LN.LN_BUG_ID,', ') WITHIN GROUP(ORDER BY LN.LN_BUG_ID)
END AS Defect_ID
FROM Test LEFT JOIN LINK LN ON
    LN.LN_ENTITY_ID=Test.TS_TEST_ID
GROUP BY
    Test_Case_Name,
    Test_Case_Status ) AS InnerTable INNERJOIN TEST ON InnerTable.Test_Case_ID = Test.Test_Case_ID
于 2012-12-26T22:25:49.700 回答