14

我已经阅读了这篇文章并编写了这个脚本来获取某个邮箱中电子邮件的正文，该邮箱的标题以“$”开头并由某个发件人发送。

import email, getpass, imaplib, os

detach_dir = "F:\PYTHONPROJECTS" # where you will save attachments
user = raw_input("Enter your GMail username --> ")
pwd = getpass.getpass("Enter your password --> ")

# connect to the gmail imap server
m = imaplib.IMAP4_SSL("imap.gmail.com")
m.login(user, pwd)

m.select("PETROLEUM") # here you a can choose a mail box like INBOX instead
# use m.list() to get all the mailboxes

resp, items = m.search(None, '(FROM "EIA_eLists@eia.gov")')
items = items[0].split() # getting the mails id

my_msg = [] # store relevant msgs here in please
msg_cnt = 0
break_ = False
for emailid in items[::-1]:
    resp, data = m.fetch(emailid, "(RFC822)")
    if ( break_ ):
        break 
    for response_part in data:
      if isinstance(response_part, tuple):
          msg = email.message_from_string(response_part[1])
          varSubject = msg['subject']
          if varSubject[0] == '$':
              msg_cnt += 1
              my_msg.append(msg)
              print msg_cnt
              print email.message_from_string(response_part[1])
              if ( msg_cnt == 5 ):
                  break_ = True

如果我打印email.message_from_string(response_part[1])，我可以看到它包含第一个信息（标题、从、到、日期...），即全文正文。但是，我无法取回尸体本身。email.message_from_string(response_part[0])打印邮件 IDS，并且email.message_from_string(response_part[2])超出范围。email.message_from_string(response_part[1][0])也没有这样做。

谢谢并恭祝安康。

更新

现在，我几乎可以拥有正文了。但是，它仍然被首先出现的信息声明所破坏。结果我得到

From nobody Tue Dec 25 11:42:58 2012

US=3D$4.030

EastCst=3D$4.036

NewEng=3D$4.205

CenAtl=3D$4.149

LwrAtl=3D$3.921

Midwst=3D$3.984

GulfCst=3D$3.945

RkyMt=3D$4.195

WCst=3D$4.187

CA=3D$4.268

我想摆脱From nobody Tue Dec 25 11:42:58 2012哪些是信息。我知道我可以解析文本查找第一个相关行...我知道。

实现这一点的代码（插入我的第一个示例）是

  if varSubject[0] == '$':
      r, d = m.fetch(emailid, "(UID BODY[TEXT])")
      msg_cnt += 1
      my_msg.append(msg)
      print email.message_from_string(d[0][1])

你有更好的方法（没有信息字符串）？？？更多：现在获取日期的命令是什么？我知道我可以varDate = msg['date']在上面适合的地方做，但是如何获取 day-month-year ？谢谢

4

4 回答 4

14

我已经设法使用 Gmail 让它工作，它提取有用的位并将它们输出到文本文件：

import datetime
import email
import imaplib
import mailbox


EMAIL_ACCOUNT = "your@gmail.com"
PASSWORD = "your password"

mail = imaplib.IMAP4_SSL('imap.gmail.com')
mail.login(EMAIL_ACCOUNT, PASSWORD)
mail.list()
mail.select('inbox')
result, data = mail.uid('search', None, "UNSEEN") # (ALL/UNSEEN)
i = len(data[0].split())

for x in range(i):
    latest_email_uid = data[0].split()[x]
    result, email_data = mail.uid('fetch', latest_email_uid, '(RFC822)')
    # result, email_data = conn.store(num,'-FLAGS','\\Seen') 
    # this might work to set flag to seen, if it doesn't already
    raw_email = email_data[0][1]
    raw_email_string = raw_email.decode('utf-8')
    email_message = email.message_from_string(raw_email_string)

    # Header Details
    date_tuple = email.utils.parsedate_tz(email_message['Date'])
    if date_tuple:
        local_date = datetime.datetime.fromtimestamp(email.utils.mktime_tz(date_tuple))
        local_message_date = "%s" %(str(local_date.strftime("%a, %d %b %Y %H:%M:%S")))
    email_from = str(email.header.make_header(email.header.decode_header(email_message['From'])))
    email_to = str(email.header.make_header(email.header.decode_header(email_message['To'])))
    subject = str(email.header.make_header(email.header.decode_header(email_message['Subject'])))

    # Body details
    for part in email_message.walk():
        if part.get_content_type() == "text/plain":
            body = part.get_payload(decode=True)
            file_name = "email_" + str(x) + ".txt"
            output_file = open(file_name, 'w')
            output_file.write("From: %s\nTo: %s\nDate: %s\nSubject: %s\n\nBody: \n\n%s" %(email_from, email_to,local_message_date, subject, body.decode('utf-8')))
            output_file.close()
        else:
            continue
于 2016-08-03T12:52:14.040 回答
6

您可以通过执行以下任何操作来获取正文的内容

msg.as_string()
str(msg)
repr(msg)

http://docs.python.org/2.7/library/email.message.html#email.message.Message

于 2012-12-25T11:54:44.857 回答
3 
from imap_tools import MailBox

# get all attachments from INBOX and save them to files
with MailBox('imap.my.ru').login('acc', 'pwd', 'INBOX') as mailbox:
    for msg in mailbox.fetch():
        print(msg.text)
        print(msg.html)

这将需要外部 lib，但要简单得多。

https://github.com/ikvk/imap_tools

于 2020-06-29T05:47:37.283 回答
-1 
import datetime
import email
import imaplib
import mailbox
import re

EMAIL_ACCOUNT = "yourmail@yahoo.com"
PASSWORD = "password"
mail = imaplib.IMAP4_SSL('imap.mail.yahoo.com')
mail.login(EMAIL_ACCOUNT, PASSWORD)
mail.select('INBOX')
result, data = mail.search(None, '(FROM "Sender Email")','ALL')
result, data = mail.search(None, '(SUBJECT "Message")','ALL')
i = len(data[0].split())

if i == 1:
   latest_email_uid = data[0].split()[0]
   result, email_data = mail.uid('fetch', latest_email_uid, '(RFC822)')
   raw_email = email_data[0][1]
   raw_email_string = raw_email.decode('utf-8')
   email_message = email.message_from_string(raw_email_string)
   body = email_message.get_payload(decode=True)
   for part in email_message.walk():
        if part.get_content_type() == "text/plain":
           emailBody = part.get_payload(decode=True)
           print(emailBody)            
        else:
           continue
else:
  print('Email NOT ' + EMAIL_ACCOUNT  )
于 2020-06-19T22:09:54.960 回答