mysql - 将两个 Mysql SUM 选择查询合并为一个查询

Question

我有以下两个查询的 SUM 值
Query1:*

从表 1 中选择总和（价格），acc_id其中 = '555'

查询2：

从表 2 中选择总和（价格）account，其中 = '555' && active='1'

我尝试将这两个查询结合起来，但给出错误的求和结果，例如如果query1 sum is: -86500和Query2 sum is: 76000，RESULT 必须是-10500，但结果显示为数字-486000

我正在尝试这样，但我没有得到预期的结果。

SELECT SUM(t1.price + t2.price) AS TotalCredit 
FROM TABLE1 AS t1, TABLE2 AS t2 
WHERE t1.`acc_id` = '555' && t2.`Account`='555' && t2.`Active`='1'

表图像：

Answer 1

由于加入记录的数量会重复，并且您会获得更高的总和值，请尝试此

SELECT sum(prc) 
FROM (
    SELECT SUM(price) prc FROM TABLE1 WHERE acc_id = '555'
    union all 
    SELECT SUM(price) prc FROM TABLE2 WHERE account = '555' && active='1'
) a

Answer 2

尝试这个

SELECT SUM(C.TOTAL) AS TOTAL_CREDIT FROM (SELECT SUM(A.price) AS TOTAL FROM TABLE1 A WHERE A.acc_id = '555'
UNION ALL
SELECT SUM(B.price) AS TOTAL FROM TABLE2 B WHERE B.account = '555' && B.active='1') C;

Answer 3

试试看

SELECT (SUM(t1.price) + SUM(t2.price)) AS TotalCredit 
FROM TABLE1 AS t1, TABLE2 AS t2 
WHERE t1.`acc_id` = '555' && t2.`Account`='555' && t2.`Active`='1'

Answer 4

这个怎么样：

SELECT SUM(a) 
FROM
  (SELECT SUM(price) AS a
   FROM TABLE1 
   WHERE acc_id = '555'
   UNION ALL
   SELECT SUM(price) AS a
   FROM TABLE2 
   WHERE account = '555' && active='1')

Answer 5

Join有待改善。:) 如果您可以向我们展示表模式，那就更好了。这是基于一些假设样本数据的解决方案。

样本数据：

表格1：

ID  PRICE
11  200
55  300
33  200
44  100
55  500

表2：

ID  PRICE   ACTIVE
1   200     0
2   300     1
55  200     0
55  100     1
55  400     1

• SQLFIDDLE 演示

询问：

select sum(t.price) + x.tb2credit
from tb1 as t
inner join
(SELECT id, SUM(price) AS Tb2Credit 
FROM tb2
WHERE id = 55
and `Active`=1) x
on t.id = x.id

结果：

SUM(T.PRICE) + X.TB2CREDIT
1300

Answer 6

尝试这个

  SELECT (t1.price + t2.price) AS TotalCredit 
    FROM TABLE1 AS t1, TABLE2 AS t2 
    WHERE t1.`acc_id` = '555' && t2.`Account`='555' && t2.`Active`='1'

编辑：

我想你在找什么

 SELECT (SUM(t1.price)+SUM(t2.price) )/2  AS TotalCredit 
FROM Table1 AS t1, Table2 AS t2 
WHERE t1.`acc_id` = '555' && t2.`account`='555' && t2.`active`='1'

演示小提琴在这里