4

我有以下数据：

Product Price   StartDate                   EndDate
Apples  4.9     2010-03-01 00:00:00.000     2010-03-01 00:00:00.000
Apples  4.9     2010-03-02 00:00:00.000     2010-03-02 00:00:00.000
Apples  2.5     2010-03-03 00:00:00.000     2010-03-03 00:00:00.000
Apples  4.9     2010-03-05 00:00:00.000     2010-03-05 00:00:00.000
Apples  4.9     2010-03-06 00:00:00.000     2010-03-06 00:00:00.000
Apples  4.9     2010-03-09 00:00:00.000     2010-03-09 00:00:00.000
Apples  2.5     2010-03-10 00:00:00.000     2010-03-10 00:00:00.000
Apples  4.9     2010-03-11 00:00:00.000     2010-03-11 00:00:00.000
Apples  4.9     2010-03-12 00:00:00.000     2010-03-12 00:00:00.000
Apples  4.9     2010-03-13 00:00:00.000     2010-03-13 00:00:00.000
Apples  4.9     2010-03-15 00:00:00.000     2010-03-15 00:00:00.000
Apples  4.9     2010-03-16 00:00:00.000     2010-03-16 00:00:00.000

想要product, price, min(startdate), max(startdate)分组，但也应该在开始日期和结束日期分组............如下所示

期望的结果

Apples  4.9     2010-03-01 00:00:00.000     2010-03-02 00:00:00.000
Apples  2.5     2010-03-03 00:00:00.000     2010-03-03 00:00:00.000
Apples  4.9     2010-03-05 00:00:00.000     2010-03-09 00:00:00.000
Apples  2.5     2010-03-10 00:00:00.000     2010-03-10 00:00:00.000
Apples  4.9     2010-03-11 00:00:00.000     2010-03-16 00:00:00.000
4

5 回答 5

3 
SELECT  product, price, MIN(start_date), MAX(end_date)
FROM    (
        SELECT  product, price, start_date, end_date,
                ROW_NUMBER() OVER (PARTITION BY product ORDER BY startDate) rn1,
                ROW_NUMBER() OVER (PARTITION BY product, price ORDER BY startDate) rn2
        FROM    mytable
        ) q
GROUP BY
        product, price, rn2 - rn1
ORDER BY
        product, MIN(start_date), price
于 2012-12-24T12:02:43.300 回答
3

我的做法。

数据：

create table t ( producte varchar(50), 
                 price money, 
                 start_date date,
                 end_date date);

insert into t values
( 'apple', 4.9, '2012-01-01', '2012-01-01' ),
( 'apple', 4.9, '2012-01-02', '2012-01-02' ),
( 'apple', 8, '2012-01-04', '2012-01-04' ),
( 'cat', 5, '2012-01-01', '2012-01-01' ),
( 'cat', 6, '2012-01-02', '2012-01-02' ),
( 'cat', 6, '2012-01-03', '2012-01-03' );

询问：

with start_dates as (
  select 
    t.producte, t.price, t.start_date, t.end_date, t.start_date as gr_date    
  from 
    t left outer join 
    t t1 on 
        t.price = t1.price and                         --new
        t.producte = t1.producte and
        t.start_date = dateadd(day,1, t1.end_date )
  where t1.producte is null
  union all
  select 
      t.producte, t.price, t.start_date,t. end_date, gr_date
  from
      t inner join 
      start_dates t1 on  
        t.price = t1.price and                         --new
        t.producte = t1.producte and
        t.start_date = dateadd(day,1, t1.end_date )
)
select t.producte, t.price , min( t.start_date ), max( t.end_date )
from start_dates t
group by  t.producte, gr_date  ,t.price

结果：

| PRODUCTE | PRICE |   COLUMN_2 |   COLUMN_3 |
----------------------------------------------
|    apple |   4.9 | 2012-01-01 | 2012-01-02 |
|    apple |     8 | 2012-01-04 | 2012-01-04 |
|      cat |     5 | 2012-01-01 | 2012-01-01 |
|      cat |     6 | 2012-01-02 | 2012-01-03 |

解释

这是一个递归 CTE 表达式。基本查询获取每组价格的初始日期。递归查询查找具有此价格的最后一个数据。

于 2012-12-24T13:50:32.897 回答
3

这是一个SQLFiddle 演示

with t2 as 
(
select t1.*,
(select count(Price) 
  from t 
  where startdate<t1.startdate 
        and Price<>t1.price
        and Product=t1.Product
)
rng  
from t as t1
)
select Product,Price,min(startDate),max(EndDate)  
from t2 group by Product,Price,RNG
order by 3
于 2012-12-24T13:06:12.210 回答
1

这里有一个建议：对于每一行，您必须找到价格不同的最大上一个日期，然后您就可以分组。例如，对于 2010-03-11 和 2010-03-16 之间的任何行，您必须检索日期 2010-03-10，因为这是价格不同的最大上一个日期（2.5 对 4.9）。第一行将返回一个空日期，但这应该不是问题。

但是，对于一个很长的表，这种查询可能会变得很慢。因此，如果您有一些速度问题，您应该考虑添加一列并使用光标逐步填充它的可能性：您按日期循环遍历它，每次看到新价格时，您都会更改它的值。最终的分组是微不足道的。

这里有一些东西：

Select Product, Price, Min(StartDate) as StartDate, PreviousDate from (
    Select product, price, StartDate, (Select max (StartDate) from table_2 t3 where t3.price <> t2.price and t3.StartDate < t2.StartDate and t3.Product = t2.Product) as previousDate
    from table_2 t2) SQ

Group by Product, Price, PreviousDate
Order by PreviousDate
于 2012-12-24T12:32:37.050 回答
0

我相信这是迄今为止效果最好的解决方案：

WITH Calc AS (
   SELECT *,
      Grp = DateAdd(day, -Row_Number()
         OVER (PARTITION BY Product, Price ORDER BY StartDate), StartDate
      )
   FROM dbo.PriceHistory
)
SELECT Product, Price, FromDate = Min(StartDate), ToDate = Max(StartDate)
FROM Calc
GROUP BY Product, Price, Grp
ORDER BY FromDate;

自己试试这个

于 2012-12-27T03:07:48.000 回答