22

我想从源表中测量 ID 和 ATTRIBUTE 的计数，并将数据显示在下面的“所需报告”中。我正在使用 MySQL。

资源：

ID  |  DATE        |  ATTRIBUTE
--------------------------------
1   |  2012-01-14  |   XYZ
2   |  2012-03-14  |   
3   |  2012-03-15  |   XYZ
4   |  2012-04-24  |   ABC
5   |  2012-04-10  |   
6   |  2012-05-11  |   ABC

所需报告：

属性计数

   YEAR | JAN | FEB | MAR | APR | MAY | JUN | JUL | AUG | SEP | OCT | NOV | DEC
   ---------------------------------------------------------------------------
   2010 |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0 
   2011 |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0 
   2012 |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0

身份证件数

   YEAR | JAN | FEB | MAR | APR | MAY | JUN | JUL | AUG | SEP | OCT | NOV | DEC
   ---------------------------------------------------------------------------
   2010 |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0 
   2011 |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0 
   2012 |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0

完成百分比（属性计数/ ID 计数）

   YEAR | JAN | FEB | MAR | APR | MAY | JUN | JUL | AUG | SEP | OCT | NOV | DEC
   ---------------------------------------------------------------------------
   2010 |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0 
   2011 |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0 
   2012 |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0  |  0

这是我到目前为止的代码。谢谢！另外请记住，我需要从数据中的日期字段中提取月份，但不确定如何。谢谢。

SELECT YEAR(document_filing_date),MONTH(document_filing_date),COUNT(aif_id)
FROM (a_aif_remaining)
GROUP BY YEAR(document_filing_date),MONTH(document_filing_date);

建议的答案不起作用！不知道为什么，这是我得到的错误：

"#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ' COUNT(CASE WHEN MONTH(document_filing_date) = 1 THEN aif_id END) AS Jan, CO' at line 1"

SELECT YEAR(document_filing_date,
  COUNT(CASE WHEN MONTH(document_filing_date) = 1 THEN aif_id END) AS Jan,
  COUNT(CASE WHEN MONTH(document_filing_date) = 2 THEN aif_id END) AS Feb,
  COUNT(CASE WHEN MONTH(document_filing_date) = 3 THEN aif_id END) AS Mar,
  COUNT(CASE WHEN MONTH(document_filing_date) = 4 THEN aif_id END) AS Apr,
  COUNT(CASE WHEN MONTH(document_filing_date) = 5 THEN aif_id END) AS May,
  COUNT(CASE WHEN MONTH(document_filing_date) = 6 THEN aif_id END) AS Jun,
  COUNT(CASE WHEN MONTH(document_filing_date) = 7 THEN aif_id END) AS Jul,
  COUNT(CASE WHEN MONTH(document_filing_date) = 8 THEN aif_id END) AS Aug,
  COUNT(CASE WHEN MONTH(document_filing_date) = 9 THEN aif_id END) AS Sep,
  COUNT(CASE WHEN MONTH(document_filing_date) = 10 THEN aif_id END) AS Oct,
  COUNT(CASE WHEN MONTH(document_filing_date) = 11 THEN aif_id END) AS Nov,
  COUNT(CASE WHEN MONTH(document_filing_date) = 12 THEN aif_id END) AS Dec,
FROM a_aif_remaining
GROUP BY YEAR(document_filing_date);
4

2 回答 2

44

此查询将计算所有行，并且还将仅计算Attribute不为空的行，按行中的年和月分组：

SELECT
  Year(`date`),
  Month(`date`),
  Count(*) As Total_Rows,
  Count(`Attribute`) As Rows_With_Attribute
FROM your_table
GROUP BY Year(`date`), Month(`date`)

（这是因为 Count(*) 计算所有行，Count(Attibute) 计算 Attribute 不为空的所有行）

如果您需要 PIVOT 中的表，您可以使用它来仅计算 Attribute 不为空的行：

SELECT
  Year(`date`),
  Count(case when month(`date`)=1 then `Attribute` end) As Jan,
  Count(case when month(`date`)=2 then `Attribute` end) As Feb,
  Count(case when month(`date`)=3 then `Attribute` end) As Mar,
  ...
FROM your_table
GROUP BY Year(`date`)

这要计算所有行：

SELECT
  Year(`date`),
  Count(case when month(`date`)=1 then id end) As Jan,
  Count(case when month(`date`)=2 then id end) As Feb,
  Count(case when month(`date`)=3 then id end) As Mar,
  ...
FROM your_table
GROUP BY Year(`date`)

（或者，您可以使用kander 的回答中的日期，而不是计算 id）Sum(Month(。)=1)当然，您可以将这两个查询组合成这样：

SELECT
  Year(`date`),
  Count(case when month(`date`)=1 then id end) As Jan_Tot,
  Count(case when month(`date`)=1 then `Attribute` end) As Jan_Attr,
  Count(case when month(`date`)=2 then id end) As Feb_Tot,
  Count(case when month(`date`)=2 then `Attribute` end) As Feb_Attr,
  Count(case when month(`date`)=3 then id end) As Mar_Tot,
  Count(case when month(`date`)=3 then `Attribute` end) As Mar_Attr,
  ...
FROM your_table
GROUP BY Year(`date`)
于 2012-12-24T10:24:41.360 回答
1

我想出了以下方法，但感觉可能有更有效的方法来解决这个问题......

select
year(`date`) as 'YEAR',
sum(month(`date`) = 1) as 'JAN',
sum(month(`date`) = 2) as 'FEB',
sum(month(`date`) = 3) as 'MAR',
    -- Repeat until december
FROM `source`
WHERE `ATTRIBUTE` = 'XYZ'
GROUP BY 1;
于 2012-12-24T10:28:51.867 回答