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我正在构建登录表单，如 symfony 2.1 文档中所示。我也在做同样的事情。我在简单授权中获得了成功，但是当我创建简单的登录表单时，我找不到 login_check 路由。如果我把 login_check 路由然后我得到 login_check 错误。
文档对此只字未提。我的 security.yml 是

# app/config/security.yml
security:
  providers:
    in_memory:
        memory:
            users:
                ryan:  { password: ryanpass, roles: 'ROLE_USER' }
                admin: { password: kitten, roles: 'ROLE_ADMIN' }

firewalls:
    login:
        pattern:  ^/login$
        security: false
    secured_area:
        pattern:    ^/admin
        anonymous: false
        form_login:
            login_path: /login
            check_path: /login_check
            always_use_default_target_path: false
            default_target_path:            /admin/content/index
            target_path_parameter:          _target_path
            use_referer:                    false
            username_parameter:             _username
            password_parameter:             _password
            csrf_parameter:                 login[_token]
        logout: 
            path: /admin/logout
            target: /login
access_control:
    - { path: ^/login, roles: IS_AUTHENTICATED_ANONYMOUSLY }
    - { path: ^/admin, roles: ROLE_ADMIN }

encoders:
    Symfony\Component\Security\Core\User\User: plaintext

和 routing.yml 是

login:
pattern:  /login
defaults: { _controller: AcmeTaskBundle:Default:login}

login_check:
pattern: /login_check        
defaults: { _controller: AcmeTaskBundle:Default:loginCheck}

logout:
pattern: /admin/logout
defaults: { _controller: AcmeTaskBundle:Default:logout}
content_index:
pattern: /admin/content/index
defaults: { _controller: AcmeTaskBundle:Default:index }

我的控制器登录操作是

namespace Acme\TaskBundle\Controller;
use Symfony\Bundle\FrameworkBundle\Controller\Controller;
use Symfony\Component\HttpFoundation\Request;
use Acme\TaskBundle\Entity\Product;
use Acme\TaskBundle\Entity\CmsContentMst;
use Acme\TaskBundle\Entity\CmsSectionsMst;

// use Acme\TaskBundle\Entity\ProductType;
use Symfony\Component\HttpFoundation\Response;
use Acme\TaskBundle\Form\Type\AddContent;
use Symfony\Component\Security\Core\SecurityContext;

class DefaultController extends Controller
{   
public function loginAction()
{
    $request = $this->getRequest();
    $session = $request->getSession();

    // get the login error if there is one
    if ($request->attributes->has(SecurityContext::AUTHENTICATION_ERROR)) {
        $error = $request->attributes->get(
            SecurityContext::AUTHENTICATION_ERROR
        );
    } else {
        $error = $session->get(SecurityContext::AUTHENTICATION_ERROR);
        $session->remove(SecurityContext::AUTHENTICATION_ERROR);
    }

    return $this->render(
        'AcmeTaskBundle:Default:login.html.twig',
        array(
            // last username entered by the user
            'last_username' => $session->get(SecurityContext::LAST_USERNAME),
            'error'         => $error,
        )
    );
  }
public function panelAction(Request $request)
{   

}
public function loginCheckAction()
  { 

    return new Response('true');

  }

和 login.html.twig 是

{# src/Acme/SecurityBundle/Resources/views/Security/login.html.twig #}
{% if error %}
  <div>{{ error.message }}</div>
{% endif %}

 <form action="{{ path('login_check') }}" method="post">
<label for="username">Username:</label>
<input type="text" id="username" name="_username" value="{{ last_username }}" />

<label for="password">Password:</label>
<input type="password" id="password" name="_password" />

{#
    If you want to control the URL the user is redirected to on success (more details      below)
    <input type="hidden" name="_target_path" value="/account" />
   #}

 <button type="submit">login</button>
 </form>

我应该在登录 check.controller 中输入什么...如果有人在 symfony 2.1 中有完整的登录示例，请把它放在答案中。

4

1 回答 1

0

您不必为 login_check 创建控制器。Symfony 已经默认定义了它的功能。我想你不会想惹它的。如果您想在登录后执行操作，您可以在服务等上定义它。

这可能对 Symfony2 有所帮助：成功登录事件后，执行一组操作

于 2012-12-26T09:52:06.300 回答