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我正在尝试在我的应用程序中显示地图，它适用于我的模拟器和我的 ipod touch 4g。

但我的 iPhone 总是出错，我不知道为什么会这样。也许你可以解释为什么它失败了。错误是：

由于未捕获的异常“NSInvalidArgumentException”而终止应用程序，原因：“无效区域<center:nan, nan span:nan, nan>”

我已经在 google 和 stackoverflow 上搜索了解决方案，但似乎没有人有这个问题。

那是我的代码：

//setup mapview
mapView.delegate = self;
mapView.showsUserLocation = YES;

//set up core location
locationManager = [[CLLocationManager alloc] init];
locationManager.delegate = self;

//Set up zoom location
CLLocationCoordinate2D zoomLocation;
zoomLocation.latitude = locationManager.location.coordinate.latitude;
zoomLocation.longitude= locationManager.location.coordinate.longitude;

debug(@"Location: %f und %f",locationManager.location.coordinate.latitude,locationManager.location.coordinate.longitude);

//zoom to location
MKCoordinateRegion viewRegion = MKCoordinateRegionMakeWithDistance(zoomLocation, 0.5*METERS_PER_MILE, 0.5*METERS_PER_MILE);
MKCoordinateRegion adjustedRegion = [mapView regionThatFits:viewRegion];                
[mapView setRegion:adjustedRegion animated:YES];

正如我所说，它适用于 iPod 和模拟器，但不适用于 iPhone。

希望你能帮我

解决方案：

我太早使用locationManager，所以应用程序崩溃了。现在我这样使用它：

      - (void)viewDidLoad {
[super viewDidLoad];

//setup mapview
mapView.delegate = self;
mapView.showsUserLocation = YES;

//set up core location
locationManager = [[CLLocationManager alloc] init];
locationManager.delegate = self;

[locationManager startUpdatingLocation];

    }

   - (void)locationManager:(CLLocationManager *)manager didUpdateToLocation:(CLLocation *)newLocation fromLocation:(CLLocation *)oldLocation{
//Set up zoom location
CLLocationCoordinate2D zoomLocation;
zoomLocation.latitude = newLocation.coordinate.latitude;
zoomLocation.longitude= newLocation.coordinate.longitude;

MKCoordinateRegion viewRegion = MKCoordinateRegionMakeWithDistance(zoomLocation, 0.5*METERS_PER_MILE, 0.5*METERS_PER_MILE);
MKCoordinateRegion adjustedRegion = [mapView regionThatFits:viewRegion];
[mapView setRegion:adjustedRegion animated:YES];

debug(@"Location: %f und %f",newLocation.coordinate.latitude,newLocation.coordinate.longitude);


    }

不知道这种方法是否 100% 正确，但它确实有效。

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