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我正在使用 libevent 在特定时间间隔内获取网站的一些统计信息。我的程序基于。我唯一缺少的是请求超时,最好是亚秒级精度。

我尝试了几件事,但无法使其正常工作。我真的很感激对此的任何指示。

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1 回答 1

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这是一个非常粗略的例子:我使用 libevent 计时器来实现超时。这可以通过将计时器放在结构中并在回调中取消它来进一步改进。

#include <stdio.h>
#include <event.h>
#include <evhttp.h>
#include <stdlib.h>
#include <unistd.h>


struct http_client {
    struct evhttp_connection *conn;
    struct evhttp_request *req;
    bool finished;
};

void _reqhandler(struct evhttp_request *req, void *state) {
    struct http_client *hc = (http_client*)state;
    hc->finished = true;

    if (req == NULL) {
        printf("timed out!\n");
    } else if (req->response_code == 0) {
        printf("connection refused!\n");
    } else if (req->response_code != 200) {
        printf("error: %u %s\n", req->response_code, req->response_code_line);
    } else {
        printf("success: %u %s\n", req->response_code, req->response_code_line);
    }
    event_loopexit(NULL);
}

void timeout_cb(int fd, short event, void *arg) {
    struct http_client *hc = (http_client*)arg;
    printf("Timed out\n");

    if (hc->finished == false){ // Can't cancel request if the callback has already executed
        evhttp_cancel_request(hc->req);
    }
}

int main(int argc, char *argv[]) {
    struct http_client *hc = (struct http_client *)malloc(sizeof(struct http_client));
    hc->finished = false;

    struct event ev;
    struct timeval tv;

    tv.tv_sec = 3; // Timeout is set to 3.005 seconds
    tv.tv_usec = 5000;


    const char *addr = "173.194.39.64"; //google.com
    unsigned int port = 80;

    event_init();

    hc->conn = evhttp_connection_new(addr, port);
    evhttp_connection_set_timeout(hc->conn, 5);

    hc->req = evhttp_request_new(_reqhandler, (void*)hc);
    evhttp_add_header(hc->req->output_headers, "Host", addr);
    evhttp_add_header(hc->req->output_headers, "Content-Length", "0");
    evhttp_make_request(hc->conn, hc->req, EVHTTP_REQ_GET, "/");

    evtimer_set(&ev, timeout_cb, (void*)hc); // Set a timer to cancel the request after certain time
    evtimer_add(&ev, &tv);

    printf("starting event loop..\n");
    printf("\n");
    event_dispatch();

    return 0;
}
于 2012-12-22T16:28:23.100 回答