37

我试图制作一个调用外部程序的应用程序,我必须传递两个参数。它没有给出任何错误。

用 C++ 编写的program.exe,拍摄照片并修改.txt文件的内容。

Java 程序运行但它什么也不做——

这是我的示例代码:

    String[] params = new String [3];
    params[0] = "C:\\Users\\user\\Desktop\\program.exe";
    params[1] = "C:\\Users\\user\\Desktop\\images.jpg";
    params[2] = "C:\\Users\\user\\Desktop\\images2.txt";
    Runtime.getRuntime().exec(params);
4

3 回答 3

69

从这里可耻地借了这个

Process process = new ProcessBuilder("C:\\PathToExe\\MyExe.exe","param1","param2").start();
InputStream is = process.getInputStream();
InputStreamReader isr = new InputStreamReader(is);
BufferedReader br = new BufferedReader(isr);
String line;

System.out.printf("Output of running %s is:", Arrays.toString(args));

while ((line = br.readLine()) != null) {
  System.out.println(line);
}

更多信息在这里

关于如何在此处此处传递命令的其他问题

于 2012-12-21T13:37:11.207 回答
14

你也可以试试它更现代的表亲,ProcessBuilder

Java Runtime.getRuntime().exec() 替代品

于 2012-12-21T13:32:52.900 回答
2
import java.io.*;

public class Code {
  public static void main(String[] args) throws Exception {
    ProcessBuilder builder = new ProcessBuilder("ls", "-ltr");
    Process process = builder.start();

    StringBuilder out = new StringBuilder();
    try (BufferedReader reader = new BufferedReader(new InputStreamReader(process.getInputStream()))) {
        String line = null;
      while ((line = reader.readLine()) != null) {
        out.append(line);
        out.append("\n");
      }
      System.out.println(out);
    }
  }
}

在线尝试

于 2019-10-03T04:47:56.717 回答