7

我制作了自己的使用 INNER JOINS 的 SQL 字符串。这是我的功能:

string cmdstr = @"SELECT s.*, mdb.menu_name
                  FROM stocksdb s, recipelist rl
                  INNER JOIN menudb mdb  ON rl.menu_ID = mdb.menu_ID
                  WHERE rl.stock_ID = '" + stockID + "'";

var cmd = new MySqlCommand(cmdstr, db.mycon);
var dr = cmd.ExecuteReader();
while (dr.Read())
{
    var menuname = dr["menu_name"].ToString();

    stockIDTxtbox.Text = stockID;
    nameTxtBox.Text = dr["stock_name"].ToString();
    availableTxtbox.Text = dr["stock_quantity"].ToString();
    pricePerPieceTxtbox.Text = dr["stock_pricePerPiece"].ToString();
    limitTxtBox.Text = dr["stock_limit"].ToString());

    recipeList.Items.Add(new ListViewItem(new[] { menuname });
}

现在的问题是,当我单击一个项目时,stocksList ListView会有recipeList ListView多个值。像 5 行左右的相同值。

4

1 回答 1

5

缺少与stockdb 的连接。像这样的东西:

   SELECT s.*, mdb.menu_name 
   FROM stocksdb s

   INNRER JOIN recipelist rl 
   ON s.stock_ID= r1.stock_ID   <== this join was missing

   INNER JOIN menudb mdb 
   ON rl.menu_ID = mdb.menu_ID 
   WHERE rl.stock_ID = '" + stockID 
于 2012-12-21T04:04:54.450 回答