2

我在 C# 中打开串行端口时遇到了这个问题(这应该很简单;或者我想)。

当我尝试打开串口时,出现以下异常:

信号量超时期限已过。

这是执行此操作的方法。

public static void Open_TheActivePortWeWillUse(String Drone_StringNameFromUser)
{
    var TempSerialPort = new SerialPort (
        Drone_StringNameFromUser, 
        (int) SerialPortParameter.TheSerialPortSpeed);

    // Now we have a name that anybody can see and use
    OurSpecificPorts.TheActivePortWeAreUsing = TempSerialPort;      
    // We'll do 8-N-1 since almost the whole planet does that
    OurSpecificPorts.TheActivePortWeAreUsing.DataBits = 8;  
    // We'll do 8-N-1
    OurSpecificPorts.TheActivePortWeAreUsing.Parity = Parity.None;    
    // We'll do 8-N-1
    OurSpecificPorts.TheActivePortWeAreUsing.StopBits = StopBits.One;    

    OurSpecificPorts.TheActivePortWeAreUsing.DataReceived +=    
        OurBackGroundSerialPortReceiver;
    // We can now open our active port, which is what this line does
    OurSpecificPorts.TheActivePortWeAreUsing.Open();      
}

对我来说最奇怪的是我得到这个错误不一致。一半时间它可以正常工作,而另一半时间则不行

有人看到我的代码有什么明显错误吗?我错过了什么吗?

4

1 回答 1

2

在方法内声明您的 SerialPort 对象将不允许在方法关闭后访问它。这是一种打开端口的方法:

  private void OpenSerialPort(String portName)
    {
        try
        {
            serialPort1.Close();
            serialPort1.PortName = portName;
            serialPort1.BaudRate = 115200;
            serialPort1.DataBits = 8;
            serialPort1.Handshake = Handshake.None;
            serialPort1.Parity = Parity.None;
            serialPort1.RtsEnable = false;
            serialPort1.StopBits = StopBits.One;

            serialPort1.Open();

        }
        catch (Exception ex)
        {
            MessageBox.Show("Could not open serial port " + portName, "Error");
        }
    }

SerialPort 对象在类中声明:

namespace Arcadia
{
    public partial class Form1 : Form
    {
        private SerialPort serialPort1;

并且在构造函数中添加了回调:

    public Form1()
    {
        InitializeComponent();

        serialPort1.DataReceived += new SerialDataReceivedEventHandler(this.SerialPortReadCallback);

发送数据以不同的方法处理:

    private void SerialPortWrite(String writeString)
    {
        if (serialPort1.IsOpen)
        {
            serialPort1.WriteLine(writeString);
        }
    }

这是接收到的数据回调:

    private void SerialPortReadCallback(object sender, SerialDataReceivedEventArgs args)
    {
        try
        {

            while (serialPort1.BytesToRead > 0)
            {
                // Do something with the data

            }
        }
        catch (Exception ex)
        {
        }
    }
于 2012-12-20T20:53:03.303 回答