发现这个gcc/config/i386/i386.md
(见顶部的评论):
;; imul $8/16bit_imm, regmem, reg is vector decoded.
;; Convert it into imul reg, reg
;; It would be better to force assembler to encode instruction using long
;; immediate, but there is apparently no way to do so.
(define_peephole2
[(parallel [(set (match_operand:SWI248 0 "register_operand")
(mult:SWI248
(match_operand:SWI248 1 "nonimmediate_operand")
(match_operand:SWI248 2 "const_int_operand")))
(clobber (reg:CC FLAGS_REG))])
(match_scratch:SWI248 3 "r")]
"TARGET_SLOW_IMUL_IMM8 && optimize_insn_for_speed_p ()
&& satisfies_constraint_K (operands[2])"
[(set (match_dup 3) (match_dup 2))
(parallel [(set (match_dup 0) (mult:SWI248 (match_dup 0) (match_dup 3)))
(clobber (reg:CC FLAGS_REG))])]
{
if (!rtx_equal_p (operands[0], operands[1]))
emit_move_insn (operands[0], operands[1]);
})
似乎它与指令解码有关(对不起,我不是专家)