2

我已经问过一个关于这个问题的问题，但是当我在我的 Web 应用程序中取得进展时，我再次偶然发现了这个问题，因为那里的答案给了我一个新问题。使用该解决方案时，我遇到的问题是更新按钮没有读取我的 gridview 文本框中的新值，而是读取了旧值。

代码隐藏

有了这个它不使用新值：

protected void Page_Load(object sender, EventArgs e)
    {
        LoadData();
        if (!Page.IsPostBack)
        {
            DataBinder();
        }
    }

    private void DataBinder()
    {
        Grid30.DataBind();
        Grid31.DataBind();
        Grid32.DataBind();
        Grid33.DataBind();
        Grid34.DataBind();
        Grid35.DataBind();
        Grid36.DataBind();
        Grid37.DataBind();
        Grid38.DataBind();
        Grid40.DataBind();
        Grid41.DataBind();
        Grid42.DataBind();
        Grid43.DataBind();
        Grid44.DataBind();
        Grid45.DataBind();
        Grid51.DataBind();
        Grid52.DataBind();
        Grid53.DataBind();
        Grid54.DataBind();
        Grid55.DataBind();
        Grid56.DataBind();
        Grid57.DataBind();
        Grid58.DataBind();
        Grid61.DataBind();
        Grid62.DataBind();
        Grid63.DataBind();
        Grid64.DataBind();
    }

有了这个，它得到了新的价值，但它不再刷新：

    protected void Page_Load(object sender, EventArgs e)
    {
        LoadData();
        DataBinder();

    }

    private void DataBinder()
    {
        if (!Page.IsPostBack)
        {
            Grid30.DataBind();
            Grid31.DataBind();
            Grid32.DataBind();
            Grid33.DataBind();
            Grid34.DataBind();
            Grid35.DataBind();
            Grid36.DataBind();
            Grid37.DataBind();
            Grid38.DataBind();
            Grid40.DataBind();
            Grid41.DataBind();
            Grid42.DataBind();
            Grid43.DataBind();
            Grid44.DataBind();
            Grid45.DataBind();
            Grid51.DataBind();
            Grid52.DataBind();
            Grid53.DataBind();
            Grid54.DataBind();
            Grid55.DataBind();
            Grid56.DataBind();
            Grid57.DataBind();
            Grid58.DataBind();
            Grid61.DataBind();
            Grid62.DataBind();
            Grid63.DataBind();
            Grid64.DataBind();
        }
    }

更新/加载数据代码

    protected void Grid36_RowUpdating(object sender, GridViewUpdateEventArgs e)
    {

        GridViewRow row = Grid36.Rows[e.RowIndex];

        var txtQuantity = (TextBox)row.FindControl("Spoor36TB");
        int quantity = int.Parse(txtQuantity.Text);

        Grid36.EditIndex = -1;
        DataBinder();
    }

    private void LoadData()
    {
        foreach(Rail rail in getAllPositions())
        {
            DataTable dt = new DataTable();
            dt.Columns.Add(new DataColumn(rail.RailNr.ToString(), typeof(string)));
            for (int i = 0; i < rail.AmountOfPositions; i++)
            {
                DataRow dr = dt.NewRow();
                dr[rail.RailNr.ToString()] = "1";
                dt.Rows.Add(dr);
            }
            DataSources(rail.RailNr, dt);
        }
    }

编辑 好吧，我删除了 DataBinder(); 在 Grid36_RowEditing() 下。这不是真正的解决方案，但目前是一个糟糕的解决方法。现在我必须按两次编辑按钮，但至少我能够更新网格。虽然这对我的问题来说不是/一个可怕的解决方案，但我希望有人仍然能够给我一个真正的解决方案

    protected void Grid36_RowEditing(object sender, GridViewEditEventArgs e)
    {
        Grid36.EditIndex = e.NewEditIndex;
        //DataBinder();
    }
4

1 回答 1

0

在行更新方法中，更新数据库中的值，然后执行数据源以及数据绑定方法。

例子 ：-

GridViewRow row = (GridViewRow)GridView1.Rows[e.RowIndex];
int id = Int32.Parse(GridView1.DataKeys[e.RowIndex].Value.ToString());
TextBox tname = (TextBox)row.FindControl("nam");
TextBox tques = (TextBox)row.FindControl("que");
MySqlCommand cmd = new MySqlCommand("update exam set name1=@name,ques=@ques where id = @id", con);
cmd.Parameters.Add("@id", MySqlDbType.Int16).Value = id;
cmd.Parameters.Add("@name", MySqlDbType.VarChar, 30).Value = tname.Text.Trim();
cmd.Parameters.Add("@ques", MySqlDbType.VarChar,40).Value = tques.Text.Trim();
con.Open();
cmd.ExecuteNonQuery();
GridView1.EditIndex = -1;
// Bind grid now
 GridView1.DataSource= dt; // get data from database
 GridView1.Databind();
于 2013-01-03T05:39:11.177 回答