5

我有一个 C# 中的 Windows 应用程序,我需要调用一个表单,其名称在运行时保存到一个字符串变量中。

像;

我已经有了表格;登录.cs

string formToCall = "Login"
Show(formToCall)

这可能吗 ?

4

5 回答 5

7

看看Activator.CreateInstance(String, String)

Activator.CreateInstance("Namespace.Forms", "Login");

您还可以使用Assembly该类(在System.Reflection命名空间中):

Assembly.GetExecutingAssembly().CreateInstance("Login");
于 2012-12-20T15:33:51.037 回答
4

使用反射:

//note: this assumes all your forms are located in the namespace "MyForms" in the current assembly.

string formToCall = "Login"
var type = Type.GetType("MyForms." + formtocall);
var form = Activator.CreateInstance(type) as Form;

if (form != null)
   form.Show();
于 2012-12-20T15:34:03.403 回答
2

要获得更多动态,您可以将表单放在任何文件夹中:

public static void OpenForm(string FormName)
{
    var _formName = (from t in System.Reflection.Assembly.GetExecutingAssembly().GetTypes()
                     where t.Name.Equals(FormName)
                     select t.FullName).Single();
    var _form = (Form)Activator.CreateInstance(Type.GetType(_formName));
    if (_form != null) 
    _form.Show();
}
于 2016-11-15T08:45:21.567 回答
1

试试这个:

var form = System.Reflection.Assembly.GetExecutingAssembly().CreateInstance(formToCall);
form.Show();
于 2012-12-20T15:33:25.907 回答
0

(Form)Assembly.GetExecutingAssembly().CreateInstance()

    Form frm = (Form)Assembly.GetExecutingAssembly().CreateInstance("namespace.form");
    frm.Show();
于 2015-09-03T19:42:33.540 回答