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我想请教一些想法支持如何在 PHP 中实现从 5 个不同的 MYSQL 脚本创建表。他们每个人的结果是按月计算的数据组的总和。我不想在脚本上花费太多时间，因为单独激活时它们都可以。

我将提出理论查询，以免我的信息太长。

<?php
$qry = "SUM(CASH) group by MONTH DESC";
$result=mysql_query($qry) or die(mysql_error());

$qry2 = "SUM(DEBT) group by MONTH DESC";
$result=mysql_query($qry2) or die(mysql_error());

$qry3 = "SUM(DEBTPAID) group by MONTH DESC";
$result=mysql_query($qry3) or die(mysql_error());

$qry4 = "SUM(INVOICE) group by MONTH DESC";
$result=mysql_query($qry4) or die(mysql_error());

$qry5 = "SUM(NVOICEPAYOFF) group by MONTH DESC";
$result=mysql_query($qry5) or die(mysql_error());
?>

我想实现这样的表：

<table>
<tr>
  <td>CASH</td>
  <td>DEBT</td>
  <td>DEBTPAID</td>
  <td>INVOICE</td>
  <td>INVOICEPAYOFF</td>
</tr>
<?
echo '<tr>';

echo '<td><label>'. $row['CASH'] .'</label></td>';
echo '<td><label>'. $row2['DEBT'] .'</label></td>';
echo '<td><label>'. $row3['DEBTPAID'] .'</label></td>';
echo '<td><label>'. $row4['INVOICE'] .'</label></td>';
echo '<td><label>'. $row5['INVOICEPAYOFF'] .'</label></td>';
echo '</tr>';

?>
</table>

我会欣赏您的每一个想法、解决方案或建议。先感谢您！

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1 回答 1

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为什么不这样做？

SELECT sum(cash) as 'cash', sum(debt) as 'debt',
  sum(debtpaid) as 'debtpaid', sum(invoice) as 'invoice',
  sum(invoicepaid) as 'invoicepaid'
FROM my_table
GROUP BY MONTH DESC
于 2012-12-20T16:55:14.780 回答