c# - 正则表达式问题 c# 数字现在是下划线

Question

我的正则表达式正在删除字符串中的所有数字 (0-9)。我不明白为什么所有数字都被替换为_

编辑：我知道我的“_”正则表达式模式将字符更改为下划线。但不是为什么数字！

谁能帮我吗？我只需要像所有特殊字符一样删除。

在此处查看正则表达式：

 string symbolPattern = "[!@#$%^&*()-=+`~{}'|]";
Regex.Replace("input here 12341234" , symbolPattern, "_");

Output: "input here ________"

score 8 · Accepted Answer

The problem is your pattern uses a dash in the middle, which acts as a range of the ascii characters from ) to =. Here's a breakdown:

As you can see, numbers start at 49, and falls between the range of 41-61, so they're matched and replaced.

You need to place the - at either the beginning or end of the character class for it to be matched literally rather than act as a range:

"[-!@#$%^&*()=+`~{}'|]"

score 4 · Accepted Answer

you must escape - because sequence [)-=] contains digits

string symbolPattern = "[!@#$%^&*()\-=+`~{}'|]";

score 2 · Accepted Answer

Move the - to the end of the list so it is seen as a literal:

"[!@#$%^&*()=+`~{}'|-]"

Or, to the front:

"[-!@#$%^&*()=+`~{}'|]"

As it stands, it will match all characters in the range )-=, which includes all numerals.

score 1 · Accepted Answer

你需要在你的正则表达式中转义你的特殊字符。例如，* 是通配符匹配。看看其中一些特殊字符对您的比赛意味着什么。

score 0 · Accepted Answer

我没有使用 C#，但通常“*”字符也是需要转义的控制字符。

以下匹配一整行任何字符，尽管“^”和“$”有些多余：

^.*$

这匹配出现在字符串中的任意数量的“A”字符：

A*

来自 oreilly 的“猫头鹰”书是您真正需要研究的：

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