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您好，我是 android 新手，我需要使用 Share Intent 分享图片。为此，我使用以下 AsyncTask。

public class ShareImageTask extends AsyncTask<String, String, String> {
    private Context context;
    private ProgressDialog pDialog;
    String image_url;
    URL myFileUrl;

    String myFileUrl1;
    Bitmap bmImg = null;
    Intent share;
    File file;

    public ShareImageTask(Context context) {
        this.context = context;
    }

    @Override
    protected void onPreExecute() {
        // TODO Auto-generated method stub

        super.onPreExecute();

        pDialog = new ProgressDialog(context);
        pDialog.setMessage("Downloading Image ...");
        pDialog.setIndeterminate(false);
        pDialog.setCancelable(false);
        pDialog.show();

    }

    @Override
    protected String doInBackground(String... args) {
        // TODO Auto-generated method stub

        try {

            myFileUrl = new URL(args[0]);
            HttpURLConnection conn = (HttpURLConnection) myFileUrl
                    .openConnection();
            conn.setDoInput(true);
            conn.connect();
            InputStream is = conn.getInputStream();
            bmImg = BitmapFactory.decodeStream(is);
        } catch (IOException e) {
            e.printStackTrace();
        }
        try {

            String path = myFileUrl.getPath();
            String idStr = path.substring(path.lastIndexOf('/') + 1);
            File filepath = Environment.getExternalStorageDirectory();
            File dir = new File(filepath.getAbsolutePath()
                    + "/Google Image Wallpaper/");
            dir.mkdirs();
            String fileName = idStr;
            file = new File(dir, fileName);
            FileOutputStream fos = new FileOutputStream(file);
            bmImg.compress(CompressFormat.JPEG, 75, fos);
            fos.flush();
            fos.close();

        } catch (Exception e) {
            e.printStackTrace();
        }

        return null;
    }

    @Override
    protected void onPostExecute(String args) {
        // TODO Auto-generated method stub
        pDialog.dismiss();
        share = new Intent(Intent.ACTION_SEND);
        share.setType("image/jpeg");

        share.putExtra(Intent.EXTRA_STREAM, file);

        startActivity(Intent.createChooser(share, "Share Image"));

    }

}

现在我必须通过传递图像 URL 来调用这个 ShareImageTask。但是我不知道怎么称呼这个？？？

例如 ：-

String Imageurl="my imageurl";
new ShareImageTask(Imageurl).execute();
4

4 回答 4

1

你可以这样称呼ShareImageTask：

String Imageurl="my imageurl";
new ShareImageTask(Curent_Activity.this).execute(Imageurl);

并将您的 InonPostExecute代码更改为：

@Override
protected void onPostExecute(String args) {
    // TODO Auto-generated method stub
    pDialog.dismiss();
    share = new Intent(Intent.ACTION_SEND);
    share.setType("image/jpeg");

    share.putExtra(Intent.EXTRA_STREAM,Uri.parse(file.getAbsolutePath().toString()));

    context.startActivity(Intent.createChooser(share, "Share Image"));

}
于 2012-12-20T07:20:57.107 回答
0

只需这样做..

ShareImageTask task = new ShareImageTask();
task.execute(Imageurl);
于 2012-12-20T07:19:20.133 回答
0

只需要在您的代码中更改一些..

你这样写

new ShareImageTask(Imageurl).execute();

但你必须这样写

new ShareImageTask(getApplicationContext()).execute(Imageurl);

您的 creat 构造函数仅带有Context参数，因此您只需在 intilize 时仅传递 ContextShareImageTask class

像下面的代码：

类定义：

public ShareImageTask(Context context) {
        this.context = context;
    }

类初始化；

new ShareImageTask(getApplicationContext());
于 2012-12-20T07:20:51.553 回答
0

将您的 AsyncTask 构造函数更改为这样

public ShareImageTask(Context context,String image_url) {
        this.context = context;
        this.image_url = image_url;
}

所以，你可以这样打电话

String Imageurl="my imageurl";
new ShareImageTask(getApplicationContext(),Imageurl).execute();
于 2012-12-20T07:17:07.780 回答