sql - 从列值中删除多余的空间

Question

我在 Oracle 数据库中有一个列，其中存储了连接值。例如，

/uk/letters/default?/uk/letters/funny_letters? 
/uk/letters/letters?/library/conditionalstyle?o=3&f=11/uk/letters/funny_letters?    
/uk/workinglife/viewarticle_93?/library/conditionalstyle?/uk/financialcentre/car_tax_calculator?
/uk/job-hunting/default?/partners/msn/i-resignfinctr?/uk/letters/letters?/ 

在网址之间，有一些空格。我怎样才能删除它们？

Answer 1

UPDATE YourTable
SET YourColumn = REPLACE(YourColumn, ' ', '')

Answer 2

这为时已晚，但会帮助一些人。

select regexp_replace(column_name, '[[:space:]]+', chr(32))  from table_name;

验证后，可以如下更新表格；

UPDATE table_name
SET column_name = REGEXP_REPLACE (column_name ,'[[:space:]]+',' ');