0

以下代码显示了订购产品的单个重量：

$weightsql = 'select op.products_name, op.products_quantity , p.products_weight from ' . TABLE_ORDERS_PRODUCTS . ' op left join ' . TABLE_PRODUCTS . ' p on op.products_id = p.products_id where op.products_id =  '.$pro['products_id'];

$weightq = tep_db_query( $weightsql );

while ($weight = tep_db_fetch_array( $weightq )){

        if($category_parent_id != 0)$list_items[] = $weight['products_weight'].'   ';

}

这显示了订购的每个产品的重量。我坚持的不是显示单独的重量，而是显示总重量。例如，如果产品订购了 3 次，重量为 7 公斤，此时代码显示：

Product                   7.00  7.00  7.00

我如何让它显示总重量，21公斤？

4

4 回答 4

3

利用array_sum()

array_sum() examples
<?php
$a = array(2, 4, 6, 8);
echo "sum(a) = " . array_sum($a) . "\n";

$b = array("a" => 1.2, "b" => 2.3, "c" => 3.4);
echo "sum(b) = " . array_sum($b) . "\n";
?>
The above example will output:
sum(a) = 20
sum(b) = 6.9
于 2012-12-19T15:04:39.957 回答
0

只需在循环之前将计数器设置为 0 并在循环期间添加 do 它，如下所示：

 $total = 0;
 $weightsql = 'select op.products_name, op.products_quantity , p.products_weight from ' . TABLE_ORDERS_PRODUCTS . ' op left join ' . TABLE_PRODUCTS . ' p on op.products_id = p.products_id where op.products_id =  '.$pro['products_id'];

 $weightq = tep_db_query( $weightsql );

 while ($weight = tep_db_fetch_array( $weightq )){
      if($category_parent_id != 0) {
           $list_items[] = $weight['products_weight'].'&nbsp;&nbsp;&nbsp;';
           $total += $weight['products_weight'];
      }

 }

然后变量 $total 应该返回 21。

于 2012-12-19T15:04:53.963 回答
0

如果您已通过 id 选择产品，最简单的解决方案是将行数乘以权重。无需将其放入数组中。

于 2012-12-19T15:07:17.407 回答
0 
$weightsql = 'select op.products_name, sum(op.products_quantity * p.products_weight) as weightsum from ' . TABLE_ORDERS_PRODUCTS . ' op left join ' . TABLE_PRODUCTS . ' p on op.products_id = p.products_id where op.products_id =  '.$pro['products_id'];


echo $weight['weightsum']

感谢您的帮助 （！）

于 2012-12-19T17:02:13.167 回答