mysql - MySQL每天选择按日期DESC排序的最后一行

Question

我有数据，

Stamp                dataField1 dataFiel2
2012-05-23 23:59:59  ....        ....
2012-05-23 23:50:00  ....        ....
2012-05-24 24:43:23  ....        ....
2012-05-24 24:12:10  ....        ....
2012-05-25 25:15:00  ....        ....
2012-05-26 25:53:59  ....        ....

我想选择每一天的最后一行，结果应该是 li

Stamp                dataField1 dataFiel2
2012-05-23 23:59:59  ....        ....
2012-05-24 24:43:23  ....        ....
2012-05-26 25:53:59  ....        ....

Answer 1

SELECT MAX(Stamp) as Last, other_column FROM table GROUP BY DAY(Stamp)

Answer 2

SELECT Stamp, dataField1, dataFiel2  FROM tableName 
GROUP BY Stamp ORDER BY Stamp ASC

Answer 3

这个怎么样？

SELECT MAX(Stamp) as Stamp, dataField1, dataField2
FROM tableName
GROUP BY DAYOFYEAR(Stamp)

我会说使用 而不是像每个人所说的那样。不同之处，请参见下面的链接。DAYOFYEAR DAY

演示

在这个演示中，DAY给出了 3 行是不正确的，而不是4 行使用DAYOFYEAR.

Answer 4

试试这个查询 -

SELECT
  Stamp, dataField1, dataField2, dataField3
FROM
  (SELECT * FROM table ORDER BY Stamp DESC) t
GROUP BY
  DATE(Stamp)