我有三个 php 脚本。main.php questions.php 和 values.php
这是代码
主文件
<html>
<head>
<title></title>
</head>
<body>
<h1>Be Prepare for the battle</h1>
<?php
$strTitle = "Begin";
$strLink = "<a href = 'question.php?ques_id=1'>" . $strTitle ."</a>";
echo $strLink;
?>
</body>
</html>
问题.php
<?php
require_once('../connect.php');
$quesSQL = mysql_query("SELECT * FROM `questions` WHERE `ques_id`=". $_GET["ques_id"]);
if(!mysql_num_rows($quesSQL) >= 1)
{
die('Complete.');
}
$next = $_GET["ques_id"];
while($row = mysql_fetch_array($quesSQL)) {
$id = $row['ques_id'];
$strTitle = $row['ques_title'];
echo "<li>" . $strTitle . "</li><br/>";
}
$optSQL = mysql_query("SELECT `options`,`values` FROM questions_options WHERE " . $id . "= ques_id");
echo "<form action=\"values.php\" method=\"POST\">";
while($row = mysql_fetch_array($optSQL) ) {
$strOptions = $row['options'];
$strValues = $row['values'];
echo "<input type =\"radio\" name =\"valueIn\" value=" . $strValues . " />" . $strOptions . "<br/>";
}
echo "</form>";
$strTitle = "<input type =\"submit\" value=\"Next\">";
$next = $next + 1;
$strLink = "<a href = 'values.php?ques_id=" . $next . "'>" . $strTitle ."</a>";
echo $strLink;
mysql_close();
?>
值.php
<?php
require_once('../connect.php');
$input = $_POST['valueIn'];
$ansSQL = mysql_query("SELECT `answer` FROM questions WHERE 1-".$_GET["ques_id"]."= ques_id");
$marks = 0;
if($input == $ansSQL)
{
$marks = $marks+1;
}
else
{
$marks = $marks+0;
}
echo $marks;
?>
现在的问题是我必须将一个值从第二个脚本(questions.php)传递给第三个脚本(values.php)。它来自单选按钮名称值“ valueIn ”中的 <form> 部分。但我不能那样做。因为我在第二个脚本的末尾发送了另一个带有 $strLink 变量的值 ques_id。那么我该怎么做呢?