6

我正在使用DotNetOpenAuth将 openID 集成到我们的 Web 应用程序中。下面的代码向提供者请求信息。

try
{
  var req = openid.CreateRequest(Request.Form["openid_identifier"]);
  req.AddExtension(new DotNetOpenAuth.OpenId.Extensions.SimpleRegistration.ClaimsRequest
  {
    Email = DotNetOpenAuth.OpenId.Extensions.SimpleRegistration.DemandLevel.Require,
    FullName = DotNetOpenAuth.OpenId.Extensions.SimpleRegistration.DemandLevel.Require,
    Nickname = DotNetOpenAuth.OpenId.Extensions.SimpleRegistration.DemandLevel.Request,
    PostalCode = DotNetOpenAuth.OpenId.Extensions.SimpleRegistration.DemandLevel.Request
  });

  return req.RedirectingResponse.AsActionResult();
}

出于某种原因,来自 openID 提供者的响应从未附带我请求的信息。下面是代码:

// Stage 3: OpenID Provider sending assertion response
switch (response.Status) {
  case AuthenticationStatus.Authenticated:
    Session["FriendlyIdentifier"] = response.FriendlyIdentifierForDisplay;
    FormsAuthentication.SetAuthCookie(response.ClaimedIdentifier, false);
    if (!string.IsNullOrEmpty(returnUrl)) {
       return Redirect(returnUrl);
    } else {
       return RedirectToAction("Index", "Home");
    }

我已经尝试过:response.ClaimedIdentifier 以一百万种方式,它从来没有我可以做的有价值的信息。有任何想法吗?

4

1 回答 1

6

IAuthenticationResponse.ClaimedIdentifier属性从不包含您请求的这些属性。它只包含 OpenID 用户的“用户名”。

您正在完美地发送请求。只需在您对积极响应的处理中添加一点:

// Stage 3: OpenID Provider sending assertion response
switch (response.Status) { 
  case AuthenticationStatus.Authenticated:
    Session["FriendlyIdentifier"] = response.FriendlyIdentifierForDisplay; 
    FormsAuthentication.SetAuthCookie(response.ClaimedIdentifier, false);
    var sreg = response.GetExtension<ClaimsResponse>();
    if (sreg != null) { // the Provider MAY not provide anything
      // and even if it does, any of these attributes MAY be missing
      var email = sreg.Email;
      var fullName = sreg.FullName;
      // get the rest of the attributes, and store them off somewhere.
    }
    if (!string.IsNullOrEmpty(returnUrl)) {
      return Redirect(returnUrl);
    } else {
       return RedirectToAction("Index", "Home");
    }
  break;
  // ...
于 2009-09-08T14:28:56.670 回答