-1

给定存储过程的输入值,如下所示:

264#20,241#15,228#10

我怎样才能将其转换为如下表?

ID1     ID2
264     20
241     15
228     10

谢谢

4

1 回答 1

0

你可以在存储过程中使用这样的东西:

;with cte (item, col1) as
(
  select 
    cast(left(col1, charindex(',',col1+',')-1) as varchar(50)) item,
         stuff(col1, 1, charindex(',',col1+','), '') col1
  from yourtable
  union all
  select 
    cast(left(col1, charindex(',',col1+',')-1) as varchar(50)) item,
    stuff(col1, 1, charindex(',',col1+','), '') col1
  from cte
  where col1 > ''
),
s2 (id1, id2) as
(
  select substring(item, 1, charindex('#', item)-1), 
    reverse(substring(reverse(item), 1, charindex('#', reverse(item))-1))
  from cte
)
select id1, id2
from s2

请参阅带有演示的 SQL Fiddle

结果:

| ID1 | ID2 |
-------------
| 264 |  20 |
| 241 |  15 |
| 228 |  10 |
于 2012-12-18T15:25:46.380 回答