0

I have data stored in mysql database, the data is encoded in ascii because of some special characters, i am trying to fetch data for iphone application, the json format is correct but due to special characters it returned me null 42756666616c6f205068696c6c79e28099732077696e67732c20636865657365737465616b7320616e64206d6f7265 this is stored in mysql桌子虽然实际上是Buffalo Philly 的翅膀、奶酪 牛排等等，但我尝试了 html_entity_decode、html2text 但没有人帮助我，请帮助我，我真的被困住了。

这是我如何从 db 获取数据并以 json 格式打印的代码：

$sql = "SELECT  p.product_id,p.image,p.model,d.name,d.product_id,d.language_id  FROM product AS p ,product_description AS d

        WHERE 
        d.product_id = p.product_id
        AND
        d.language_id = 1

        ORDER BY p.date_added


        limit 10
    ";

$rs = mysql_query($sql);
$data = array();
$products = '{"products":{';
$num = mysql_num_rows($rs);

while($d = mysql_fetch_array($rs)){
$image = new SimpleImage();
$image->load($path.$d['image']);
$image->resize(55,55);
$img = strtotime("now").$count;
$image->save("images/".$img.'.jpg');
$pimage = "$img_url/$img.jpg";

$name = html_entity_decode($d['name'],ENT_QUOTES, 'UTF-8');


$highlight = html_entity_decode($d['model'],ENT_QUOTES, 'UTF-8');


if($count < $num){
    $products .= '"'.$d["product_id"].'":[
                                            {
                                                "id":"'.$d["product_id"].'",
                                                "name":"'.$name.'",
                                                "image_url":"'.$pimage.'",
                                                "highlight":"'.$highlight.'"
                                            }
                                        ],';
    }else{
    $products .= '"'.$d["product_id"].'":[
                                            {
                                                "id":"'.$d["product_id"].'",
                                                "name":"'.$d["name"].'",
                                                "image_url":"'.$pimage.'",
                                                "highlight":"'.$highlight.'"
                                            }
                                        ]';
}

}
$products .='}}';

print($products);

对象-c代码是：

NSData *data = [NSData dataWithContentsOfURL:soURL];
    NSError *error;
    productsRaw = [NSJSONSerialization JSONObjectWithData:data options:kNilOptions error:&error];
    products = [productsRaw objectForKey:@"products"];
    productKeys = [products allKeys];
4

1 回答 1

0

该字符串似乎是十六进制编码的。您可以使用pack功能，如下所示：

pack('H*', $data);

如this SO page中所述，或接近它的东西（'h*'包装参数可能有效）。

请注意，生成的字符串将进行语言环境编码，因此根据原始应用程序中使用的语言环境，您可能需要进行一些语言环境转换才能获得正确编码的字符串。为此，我建议使用iconv函数，但无论如何你必须知道最初使用的语言环境。

于 2012-12-18T12:35:15.070 回答