c# - GetFilesAsync 停止工作

Question

我有这段代码

public static class Storage
{
    public async static Task<bool> Exists(string filename)
    {
        var folder = await Package.Current.InstalledLocation.GetFolderAsync("Assets");
        var _files= await folder.GetFilesAsync(CommonFileQuery.OrderByName).AsTask().ConfigureAwait(false);

        var file = _files.FirstOrDefault(x => x.Name == filename);
        return file != null;
    }
}

并从我的 Windows 8 Store 应用程序中调用它；

this.IconExists = this.Game != null && Storage.Exists(this.IconName).Result;

因此，如果我在上面的行上放置一个断点并逐步运行它，它可以工作，但是没有中断并且只是运行应用程序会导致应用程序挂起。

几天前的提交也有类似的代码；

using System;
using System.Collections.Generic;
using System.Linq;
using System.Threading.Tasks;
using Windows.ApplicationModel;
using Windows.Storage;
using Windows.Storage.Search;

namespace eggrr.Core.FileStorage
{
    public class Storage
    {
        private IReadOnlyList<StorageFile> _files;

        public Storage()
        {
            _files = GetFilesAsync("Assets").Result;
        }

        private async Task<IReadOnlyList<StorageFile>> GetFilesAsync(string relativeFolderPath)
        {
            var path = string.Format("{0}\\{1}", Package.Current.InstalledLocation.Path, relativeFolderPath);
            var folder = await StorageFolder.GetFolderFromPathAsync(path);
            return await folder.GetFilesAsync(CommonFileQuery.OrderByName).AsTask().ConfigureAwait(false);
        }

        public bool Exists(string filename)
        {
            var file = _files.FirstOrDefault(x => x.Name == filename);
            return file != null;
        }

        private static readonly Storage _instance = new Storage();
        public static Storage Instance { get { return _instance; } }
    }
}

有任何想法吗？

score 3 · Accepted Answer

似乎这解决了它的问题；

    public static class Storage
{
    private static IReadOnlyList<StorageFile> _files;

    static Storage()
    {
        _files = GetFilesAsync("Assets").Result;
    }

    private async static Task<IReadOnlyList<StorageFile>> GetFilesAsync(string relativeFolderPath)
    {
        var folder = await Package.Current.InstalledLocation.GetFolderAsync("Assets").AsTask().ConfigureAwait(false);
        return await folder.GetFilesAsync(CommonFileQuery.OrderByName).AsTask().ConfigureAwait(false);
    }

    public static bool Exists(string filename)
    {
        var file = _files.FirstOrDefault(x => x.Name == filename);
        return file != null;
    }
}

更多信息；

c# - GetFilesAsync 停止工作

1 回答 1

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