java - 检查字符串是否为标点符号

Question

假设我有一个包含一些字母和标点符号的字符串数组

String letter[] = {"a","b","c",".","a"};

在字母[3]中，我们有“。”

如何检查字符串是否为标点符号？我们知道有很多可能的标点符号（,.?! 等）

到目前为止我的进展：

for (int a = 0; a < letter.length; a++) {
    if (letter[a].equals(".")) { //===>> i'm confused in this line
        System.out.println ("it's punctuation");
    } else {
        System.out.println ("just letter");
    }
}

Answer 1

这是使用正则表达式的一种方法：

if (Pattern.matches("\\p{Punct}", str)) {
    ...
}

正\p{Punct}则表达式是表示单个标点字符的 POSIX 模式。

Answer 2

Answer 3

你想检查更多的标点符号.吗？

如果是这样，您可以这样做。

String punctuations = ".,:;";//add all the punctuation marks you want.
...
if(punctuations.contains(letter[a]))

Answer 4

试试这个方法：Character.isLetter()。如果字符是字母（az、大写或小写），则返回 true，如果字符是数字或符号，则返回 false。

例如 boolean answer = Character.isLetter('!');

答案将等于假。

Answer 5

I have tried regex: "[\\p{Punct}]" or "[\\p{IsPunctuation}]" or withouth [], it doesn't work as expected.

My string is: How are you?, or even "How are you?", he asked.

Then call: my_string.matches(regex); but it seems like it only recognises if the string is only one punctuation (e.g "?", ".",...).

Only this regex works for me: "(.*)[\\p{P}](.*)", it will include all preceding and proceeding characters of the punctuation because the matches() requires to match all the sentence.

Answer 6

import String ... if(string.punctuation.contains(letter[a]))

Answer 7

function has_punctuation(str) {

  var p_found = false;
  var punctuations = '`~!@#$%^&*()_+{}|:"<>?-=[]\;\'.\/,';
  $.each(punctuations.split(''), function(i, p) {
    if (str.indexOf(p) != -1) p_found = true;
  });

  return p_found;

}