-6

我是 C 的新手，显然我在理解所有内存和指针方面遇到了一些问题。所以我有以下Java代码：

public class Question_10
{
   public static void sortInt(int[] array)
   {
      int top = 0;
      while (top < array.length - 1)
      {
         if (array[top] < array[top + 1])
         {
            top++;
         }
         else
         {
            int temp = array[top];
            array[top] = array[top + 1];
            array[top + 1] = temp;
            if (top > 0)
            {
               top--;
            }
         }
         System.out.println(top);
      }
   }

   public static void main(String[] args)
   {
      int[] arr = {5, 6, 10, 1, 45, 3};

      sortInt(arr);
      System.out.println();
   }

}

Aaand，我做了以下事情：

#include <stdio.h>

void sortInt(int arrayInput[])
{
    int top = 0;
    int arrLen = sizeof(arrayInput)/(sizeof(int);
    while(top < arrLen - 1)
    {
        if(arrayInput[top] < arrayInput[top+1])
        {
            top++;
        }
        else
        {
            int temp = arrayInput[top];
            arrayInput[top] = arrayInput[top + 1];
            arrayInput[top + 1] = temp;
            if(top > 0)
            {
                top--;
            }
        }
        printf("%i", top);
    }
}
void main()
{

    int array[] = {5, 6, 10, 1, 45, 3};
    sortInt(array);
    return 0;
}

当然我得到了很多错误：

$ gcc Question10.c
Question10.c: In function `sortInt':
Question10.c:6: error: parse error before ';' token
Question10.c: At top level:
Question10.c:16: error: `top' undeclared here (not in a function)
Question10.c:16: warning: data definition has no type or storage class
Question10.c:17: error: `temp' undeclared here (not in a function)
Question10.c:17: warning: data definition has no type or storage class
Question10.c:18: error: parse error before "if"
Question10.c:23: error: parse error before string constant
Question10.c:23: error: conflicting types for 'printf'
Question10.c:23: note: a parameter list with an ellipsis can't match an empty parameter name list declaration
Question10.c:23: error: conflicting types for 'printf'
Question10.c:23: note: a parameter list with an ellipsis can't match an empty parameter name list declaration
Question10.c:23: warning: data definition has no type or storage class
Question10.c: In function `main':
Question10.c:30: warning: `return' with a value, in function returning void
Question10.c:27: warning: return type of 'main' is not `int'
Question10.c:31:2: warning: no newline at end of file
Question10.c: At top level:
Question10.c:16: error: storage size of `arrayInput' isn't known
Question10.c:17: error: storage size of `arrayInput' isn't known

也许您可以就问题所在给我任何建议，并且一些一般性指导会有所帮助，因为我真的迷失在 C 中的这些“对象”事物中。

4

2 回答 2

1

此行存在语法错误：

int arrLen = sizeof(arrayInput)/(sizeof(int);

尝试使用： int arrLen = sizeof(arrayInput)/sizeof(int);

如果你从修复它开始，那么你可能会解决你遇到的其他一些问题。如果没有，一次拿一个。

我可以看到的另一个错误是您将 main 方法声明为void main()并调用return 0;. 根据 C 标准， main() 方法应该返回int，所以更改声明。

于 2012-12-18T01:20:51.137 回答
1

我让它工作。

   void sortInt(int arrayInput[], int arrLen)
    {
        int top = 0;
        while(top < arrLen - 1)
        {
            if(arrayInput[top] < arrayInput[top+1])
            {
                top++;
            }
            else
            {
                int temp = arrayInput[top];
                arrayInput[top] = arrayInput[top + 1];
                arrayInput[top + 1] = temp;
                if(top > 0)
                {
                    top--;
                }
            }
            printf("%i", top);
        }
    }

    int main()
    {
        int array[] = {5, 6, 10, 1, 45, 3};
        sortInt(array, sizeof(array)/sizeof(int));
        return 0;
    }
于 2012-12-18T01:28:21.880 回答