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我有一个基于本教程的 spring mvc 3.1 应用程序。我已将应用程序修改为基于注释的应用程序，并调整视图处理程序以在 jstl 上使用 InternalResourceViewResolver，这工作正常。

简而言之，该应用程序使用 spring mvc、spring data jpa 和 jqgrid 来生成一个简单的用户列表，该列表具有基本的 crud 映射，通过响应将操作传递给控制器​​......

当我尝试通过更新操作修改记录时，我收到 500 个错误（aop 跟踪拦截器）...

例外...

    Servlet.service() for servlet [dispatcher] in context with path    
    [/spring-jqgrid-tutorial] threw exception [Request processing failed;    
    nested exception is org.springframework.dao.InvalidDataAccessApiUsageException:
    org.hibernate.QueryParameterException: 
    Position beyond number of declared ordinal parameters.    
    Remember that ordinal parameters are 1-based! 
    ...
    at org.beckett.service.UserService.update(UserService.java:32)

用户服务...

    ...   
public Boolean update( User user ) {
    User existingUser = repository.findByUsername( user.getUsername() );
    if( existingUser == null ) {
        return false;
    }
    // Only firstName, lastName, and role fields are updatable
    existingUser.setFirstName( user.getFirstName() );
    existingUser.setLastName( user.getLastName() );
    existingUser.getRole().setRole( user.getRole().getRole() );

    User saved = repository.save( existingUser );
    if( saved == null )
        return false; {

    }
    return true;
}

    ...

用户实体

    @Entity( name = "user" ) 
    @NamedQuery( name = User.FIND_BY_USERNAME, 
    query = "select u from user u where u.username = :username" )
    public class User {

    public static final String FIND_BY_USERNAME = "User.findByUsername";

    @Id @GeneratedValue( strategy = GenerationType.AUTO )
    private Long id;

    private String firstName;
    private String lastName;

    @Column( unique = true )
    private String username;

    @JsonIgnore
    private String password;

    @OneToOne( cascade =  CascadeType.ALL, mappedBy = "user" )
    private Role role;
...

用户存储库 

    public interface UserRepository extends JpaRepository<User, Long> {

    User findByUsername( String username );

    Page<User> findByUsernameLike( String username, Pageable pageable );

    Page<User> findByFirstNameLike( String firstName, Pageable pageable );

    Page<User> findByLastNameLike( String lastName, Pageable pageable );

    Page<User> findByFirstNameLikeAndLastNameLike( String firstName, String lastName, Pageable pageable );

    @Query( "select u from user u where u.role.role = :role" )
    Page<User> findByRole( @Param( "role" ) Integer role, Pageable pageable );
}

用户控制器 

    @RequestMapping( value = "/update", 
    produces = "application/json", 
    method = RequestMethod.POST )

    public @ResponseBody StatusResponse update( 
           @RequestParam String username, 
           @RequestParam String firstName, 
           @RequestParam String lastName, 
           @RequestParam Integer role ) {

       User existingUser = new User( username, firstName, lastName, new Role( role ) );
       Boolean result = service.update( existingUser );
       return new StatusResponse( result );
}

我已经看到了几个关于这个异常的线程，说明了更改 HQL 查询的要求......但是，我不确定如何调试这个问题......

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1 回答 1

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这是通过用命名查询的位置参数替换命名参数来解决的。

    @NamedQuery( name = User.FIND_BY_USERNAME, 
    query = "select u from user u where u.username = ?1" )
于 2012-12-18T01:29:20.197 回答