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我有两张桌子:一张用于发票,另一张用于付款:

tbl_Invoice

发票

tbl_payment

支付

愿望输出如下:

PSUM        IPRICE
----------- ------------
312.00      1100.00

在哪里:

PSUM是付款总和。

IPRICE是该客户的 Total_price 的总和。

我试过的查询是:

select 
IsNull(sum(p.amt), 0) PSUM,
IsNull(sum(i.total_price), 0) IPRICE
from tbl_invoice i
left join tbl_payment p
on i.invoice_id = p.invoice_id
    and i.client_id = p.client_id
where i.client_id = 5
group by i.invoice_id
order by i.invoice_id

但它给出了错误的输出:

PSUM        IPRICE
----------- ------------
312.00      400.00
0.00        1000.00
4

1 回答 1

1

好像你想要这个。amt这给出了 the和 the的总和,total_price没有分组。您的版本分组invoice_id是不同的:

select 
  IsNull(sum(p.amt), 0) PSUM,
  IsNull(sum(distinct i.total_price), 0) IPRICE
from tbl_invoice i
left join tbl_payment p
  on i.invoice_id = p.invoice_id
  and i.client_id = p.client_id
where i.client_id = 5

请参阅带有演示的 SQL Fiddle

你可以这样写的另一种方法是使用子查询:

select 
  IsNull(sum(p.amt), 0) PSUM,
  IsNull(sum(i.total_price), 0) IPRICE
from
(
  select sum(total_price) total_price, invoice_id, client_id
  from tbl_invoice
  group by invoice_id, client_id
) i
left join
(
  select sum(amt) amt, invoice_id, client_id 
  from tbl_payment
  group by invoice_id, client_id
) p
  on i.invoice_id = p.invoice_id
  and i.client_id = p.client_id
where i.client_id = 5

请参阅带有演示的 SQL Fiddle

两者都产生相同的结果:

| PSUM | IPRICE |
-----------------
|  312 |   1100 |
于 2012-12-17T11:34:35.817 回答